Javascript 包含从字符串中平均字长的函数？

这是我第一次接触JavaScript，我正在编写一个函数，该函数将输出以下内容：

字符串中的单个单词， 字符总数， 总字数， 空格计数， 最后是平均字长。 到目前为止，我已经完成了所有的方面，除了我正在努力的平均过程

我的代码：

var superCounter = function(x) {
  var charCount = x.length;
  var wordCount = x.split(" ").length;
  var whiteSpace = wordCount - 1; 
  var wordArray = [x.split(" ")];
  var wordAvg = 0;
  for (var i = 0; i < wordCount.length; i++){
    wordAvg += wordArray[i];
  }
  var avgLen = wordAvg / wordCount;
  console.log(("Words: " + wordArray[0]), "Character count: " + charCount, "Word count: " + wordCount, "Whitespace count: " + whiteSpace, "Word length average: " + avgLen);
};

superCounter("This function will analyze strings");

我知道我不知何故需要I的长度，但我尝试应用长度的每一种方法都不起作用

想法

---

谢谢大家!

您几乎成功了，只做了几处小改动，您的代码运行得很好

wordArray应声明如下：

var wordArray = x.split(" ");

然后需要将单词字符长度的总和更正为wordAvg

更改此项：

wordAvg += wordArray[i];

为此：

wordAvg += wordArray[i].length;

应该是

 wordAvg += wordArray[i].length;

---

应该是这样的：

var superCounter = function(x) {
    var charCount = x.length;
    var wordCount = x.split(" ").length;
    var whiteSpace = wordCount - 1; 
    var wordArray = x.split(" ");
    var wordAvg = 0;
    for (var i = 0; i < wordCount; i++){
        wordAvg += wordArray[i].length;
    }
    var avgLen = wordAvg / wordCount;
    console.log(("Words: " + wordArray), "Character count: " + charCount, "Word count: " + wordCount, "Whitespace count: " + whiteSpace, "Word length average: " + avgLen);
};

superCounter("This function will analyze strings");

---

也许可以试试这样：

 function jCounter(data) { 
     var strArr = data.split(' ');
     var strChar = data.length;
     var objStr = strArr.length;   
     var strSpaces = objStr - 1;

     var numArr = [];
     for (i=0; i<objStr; i++) {
        numArr.push(strArr[i].length); 
     }

     var sum = 0;
     for (i=0; i<numArr.length; i++) {
        sum = sum + numArr[i];
     } 

     var avg = sum/objStr;
     var strObj = {}; 

     strObj.words = objStr;
     strObj.chars = strChar;
     strObj.avgLength = avg ;
     strObj.spaces = strSpaces;

     console.log(strObj);
   } 

   jCounter("Coding is challenging");

---

我是一个数字。它没有长度。你是指数组中该元素的长度吗？你尝试了什么？你把字符串添加到一个数字中。说使用长度无效无助于任何人的诊断，具体发生了什么？您尝试了什么？更改此变量wordArray=[x.split]；对于该变量，wordArray=x.split；变量，然后更改此wordAvg+=wordArray[i]；对这个wordAvg+=wordArray[i].length；它是字符总数除以字数，如var avgLen=wordArray.join.length/wordCount->

var superCounter = function(x) {
    var charCount = x.length;
    var wordCount = x.split(" ").length;
    var whiteSpace = wordCount - 1; 
    var wordArray = x.split(" ");
    var wordAvg = 0;
    for (var i = 0; i < wordCount; i++){
        wordAvg += wordArray[i].length;
    }
    var avgLen = wordAvg / wordCount;
    console.log(("Words: " + wordArray), "Character count: " + charCount, "Word count: " + wordCount, "Whitespace count: " + whiteSpace, "Word length average: " + avgLen);
};

superCounter("This function will analyze strings");

 function jCounter(data) { 
     var strArr = data.split(' ');
     var strChar = data.length;
     var objStr = strArr.length;   
     var strSpaces = objStr - 1;

     var numArr = [];
     for (i=0; i<objStr; i++) {
        numArr.push(strArr[i].length); 
     }

     var sum = 0;
     for (i=0; i<numArr.length; i++) {
        sum = sum + numArr[i];
     } 

     var avg = sum/objStr;
     var strObj = {}; 

     strObj.words = objStr;
     strObj.chars = strChar;
     strObj.avgLength = avg ;
     strObj.spaces = strSpaces;

     console.log(strObj);
   } 

   jCounter("Coding is challenging");