Javascript Firebase查询如果为true,则显示键值

Javascript Firebase查询如果为true,则显示键值,javascript,firebase,firebase-realtime-database,Javascript,Firebase,Firebase Realtime Database,试图将group2成员调出控制台,因此在本例中,结果应该是user2,并且不会显示它是否不存在: { "users":{ "user1":{ "username":"john", "groups":{ "group1":true, "group3":true } }, "user2": ..., } "groups": { "group1"{

试图将
group2
成员调出控制台,因此在本例中,结果应该是
user2
,并且不会显示它是否不存在:

{
  "users":{
    "user1":{
        "username":"john",
        "groups":{
            "group1":true,
            "group3":true
        }
    },
    "user2": ...,
  }
  "groups": {
     "group1"{
        ...
      },
     "group2"{
        "group_name":"Moderators",
        "members":{
            "user2":true
        }
      }
   }
 }
我试过:

const ref = firebase.database().ref('groups');
            ref.orderByChild("user2").on("child_added", function (snapshot) {
                console.log(snapshot.key)
            });

但如果您试图列出第2组的成员,则运气不佳:

const ref = firebase.database().ref('groups');
ref.child("group2/members").on("child_added", function (snapshot) {
    console.log(snapshot.key)
});
这将打印:

用户2