jQueryAjax中的Url.Action:未传递第二个参数
我试图用jQueryAjax在jQueryAjax中的Url.Action:未传递第二个参数,jquery,ajax,razor,url.action,Jquery,Ajax,Razor,Url.action,我试图用jQueryAjax在Url.Action函数中传递两个参数,只传递第一个参数。调试时,这两个参数在ajax函数中正确显示。在数据中传递的值传递正确 我做错了什么 以下是视图中的代码: <script type="text/javascript"> $(function () { $("#sendForm").click(function () { //they both show correctly in the conso
Url.Action
函数中传递两个参数,只传递第一个参数。调试时,这两个参数在ajax函数中正确显示。在数据
中传递的值传递正确
我做错了什么
以下是视图中的代码:
<script type="text/javascript">
$(function () {
$("#sendForm").click(function () {
//they both show correctly in the console
console.log('@ViewData["recordURL"]');
console.log('@ViewData["title"]');
$.ajax({
url: '@Url.Action("SendEmail", "Search", new { title = ViewData["title"], recordURL = ViewData["recordURL"] })',
type: "POST",
data: {
//placed these here so don't have to intersperse javascript with razor code in Url.Action
recepient: $("#recepient").val(),
message: $("#message").val()
},
success: function (result) {
$(".emailForm").hide();
$(".results").text(result);
window.setTimeout(closeEmailPopup, 3500);
}
});
});
});
</script>
我想问题在于你的最终URL字符串。尝试将其包装为Html.Raw以防止转义符号(&S):
...
url: '@Html.Raw(Url.Action("SendEmail", "Search", new { title = ViewData["title"], recordURL = ViewData["recordURL"] }))',
...
摘自此
...
url: '@Html.Raw(Url.Action("SendEmail", "Search", new { title = ViewData["title"], recordURL = ViewData["recordURL"] }))',
...