JQuery将文件发送到Django
我还有一个问题。 当我发送带有表格的POST请求时:JQuery将文件发送到Django,jquery,python,ajax,django,jszip,Jquery,Python,Ajax,Django,Jszip,我还有一个问题。 当我发送带有表格的POST请求时: <form id="uploadForm" action="/theme/zip/type/" method="post" enctype="multipart/form-data"> {% csrf_token %} <input id="fileInput" class="input-file" name="upload" type="file"> <input type="submi
<form id="uploadForm" action="/theme/zip/type/" method="post" enctype="multipart/form-data">
{% csrf_token %}
<input id="fileInput" class="input-file" name="upload" type="file">
<input type="submit" value="Upload" />
</form>
服务器打印:
<MultiValueDict: {u'upload': [<InMemoryUploadedFile: ID_12241.zip (application/zip)>]}>
我在'request.POST'中的'file'参数中有此文件,但'request.FILES'为空()。
我做错了什么?传统意义上的Ajax是XMLHttpRequest,它不允许您编码本地文件并将其发送到服务器 通过“ajax”方式进行上传的常见方法是使用Flash swf在同一页面上处理上传,或者使用目标为不可见1x1 iframe的表单 试一试 或者试试看,它可以使用ajax上传文件 根据其网站上的文件
支持XMLHttpRequest级别2的浏览器将能够无缝上传文件,甚至在上传过程中获得进度更新。对于较旧的浏览器,使用涉及iFrame的回退技术,因为无法使用XMLHttpRequest对象的1级实现上载文件。
我在我的项目中使用它,您不必为旧浏览器定义任何iframe。这个插件会自动为你做这件事。下面是实现ajax文件上传的示例代码-
HTML文件如下所示(下载并链接HTML文件中的jquery.form.js):-
单击submit按钮后,将调用submit()函数。此函数返回false,这对于防止浏览器回发非常重要。
在此函数中定义了2个回调函数
showRequest
将在表单即将提交时调用,在这里您可以看到所有post数据李>
showResponse
将在服务器返回响应时调用在服务器上,您将在request.FILES中获取数据。从服务器返回一个JSON响应,可以在
showResponse
函数中访问该响应。您不能使用Ajax发送文件。
<MultiValueDict: {u'upload': [<InMemoryUploadedFile: ID_12241.zip (application/zip)>]}>
var content = zip.generate();
var options = {
url: '/theme/zip/type/',
data: {
file: content
}
};
$('#uploadForm').ajaxSubmit(options);
<form id="uploadForm" method="post" action="/theme/zip/type/"> {% csrf_token %}
<input type="file" id="fileInput" name="upload"/>
<button type="submit">Upload</button>
</form>
<script src="jquery-ui.min.js"></script>
<script src="jquery.form.js"></script>
var options = {
beforeSubmit:showRequest, // pre-submit callback
success:showResponse, // post-submit callback
resetForm: false // reset the form after successful submit
};
//uploadForm is the name of your form
$('#uploadForm').submit(function() {
// inside event callbacks 'this' is the DOM element so we first
// wrap it in a jQuery object and then invoke ajaxSubmit
$(this).ajaxSubmit(options);
// !!! Important !!!
// always return false to prevent standard browser submit and
// page navigation return false;
});
// pre-submit callback
function showRequest(formData, jqForm, options) {
// formData is an array; here we use $.param to convert it
// to a string to display it but the form plugin does
// this for you automatically when it submits the data
var queryString = $.param(formData);
// jqForm is a jQuery object encapsulating the form element.
// To access the DOM element for the form do this:
// var formElement = jqForm[0];
alert('About to submit: \n\n' + queryString);
// here we could return false to prevent the form from being submitted;
// returning anything other than false will allow the
// form submit to continue
return true;
}
// post-submit callback
function showResponse(responseText, statusText, xhr, $form) {
// for normal html responses, the first argument to the success callback
// is the XMLHttpRequest object's responseText property
// if the ajaxSubmit method was passed an Options Object with the dataType
// property set to 'xml' then the first argument to the success callback
// is the XMLHttpRequest object's responseXML property
// if the ajaxSubmit method was passed an Options Object with the dataType
// property set to 'json' then the first argument to the success callback
// is the json data object returned by the server
alert('status: ' + statusText + '\n\nresponseText: \n' + responseText +
'\n\noutput div should have been updated with the responseText.');
}