解析node.js中的JSON

如何解析node.js中的以下JSON以提取temp和city的值

{
"message":"",
"cod":"200",
"type":"base",
"calctime":"",
"units":"internal",
"count":1,
"list":
    [
        {"id":2823368,
        "coord":{"lat":47.666672,"lon":9.6},
        "name":"London",
        "main":{"temp":275.79,"pressure":1020,"humidity":74,"temp_min":272.59,"temp_max":281.48},
        "dt":1362137169,
        "date":"2013-03-01 11:26:09",
        "wind":{"speed":1.5,"deg":0},
        "clouds":{"all":90},
        "weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04d"}],
        "sys":{"country":"DE","population":18135},
        "url":"http:\/\/openweathermap.org\/city\/2823368"
        }
        ]
}

我通过以下方式获得上述JSON：

var response = JSON.parse(body);

console.log(response);

任何帮助都将不胜感激

var temp = response.list[0].main.temp;
var city = response.list[0].name;

---

至于“city”，我不确定您在寻找什么，因为您的输入中没有该名称的键，但我猜了一下。

使用下面的内容获取临时和城市（来自url的城市），或者使用名称

var temp = response.list[0].main.temp,
url = response.list[0].url,
city = url.split('/')[3],
name = response.list[0].name;