使用miller shell命令为每一行创建一个JSON对象文件，并将带有值对的哈希ID键附加到该文件中

我希望基于每个

JSON对象中的所有值，为我的
JSONs
文件中的每一行创建一个
唯一ID/hash ID

我从这里开始，但不确定是否必须使用显式列名，或者是否有一种方法可以包含所有列而不显式使用列名

mlr --json put -S '$hash_id=$f_name."".$l_name."".$title' then reorder -e -f job file.json

file.json
输入：

{"f_nams":"Hana","title":"Mrs","l_name":"Smith"}
{"f_nams":"Mike","title":"Mr","l_name":"Larry"}
{"f_nams":"Jhon","title":"Mr","l_name":"Doe"}

期望输出：

{"f_nams":"Hana","title":"Mrs","l_name":"Smith","hash_id":"hash_value_based_on_all_columns"}
{"f_nams":"Mike","title":"Mr","l_name":"Larry","hash_id":"hash_value_based_on_all_columns"}
{"f_nams":"Jhon","title":"Mr","l_name":"Doe","hash_id":"hash_value_based_on_all_columns"}

perl -MMIME::Base64 -ne '
/"f_nams":"(\w+)","title":"(\w+)","l_name":"(\w+)"/ && do {
($fn,$tt,$ln)=($1,$2,$3);
$x=$fn . $tt . $ln;
chomp($hashvalue = encode_base64($x));
s/\}/,"hash_id":"$hashvalue"\}/;print}' file.json

假设输入文件.json的格式如下所示：

cat file.json
{"f_nams":"Hana","title":"Mrs","l_name":"Smith"}
{"f_nams":"Mike","title":"Mr","l_name":"Larry"}
{"f_nams":"Jhon","title":"Mr","l_name":"Doe"}

然后，一种方法是使用以下perl脚本生成所需的输出：

{"f_nams":"Hana","title":"Mrs","l_name":"Smith","hash_id":"hash_value_based_on_all_columns"}
{"f_nams":"Mike","title":"Mr","l_name":"Larry","hash_id":"hash_value_based_on_all_columns"}
{"f_nams":"Jhon","title":"Mr","l_name":"Doe","hash_id":"hash_value_based_on_all_columns"}

perl -MMIME::Base64 -ne '
/"f_nams":"(\w+)","title":"(\w+)","l_name":"(\w+)"/ && do {
($fn,$tt,$ln)=($1,$2,$3);
$x=$fn . $tt . $ln;
chomp($hashvalue = encode_base64($x));
s/\}/,"hash_id":"$hashvalue"\}/;print}' file.json

产生：

{"f_nams":"Hana","title":"Mrs","l_name":"Smith","hash_id":"SGFuYU1yc1NtaXRo"}
{"f_nams":"Mike","title":"Mr","l_name":"Larry","hash_id":"TWlrZU1yTGFycnk="}
{"f_nams":"Jhon","title":"Mr","l_name":"Doe","hash_id":"Smhvbk1yRG9l"}

mlr
是一个非常棒的处理JSON小操作的工具，我认为最新版本中不存在哈希创建函数。您想使用
jq
一个更强大的JSON解析器来回答这个问题吗？并解释您试图创建的哈希的性质是什么
md5
或
sha
或
base64
？（后者在
jq
中得到了开箱即用的支持）当然，我想探索
jq
。现在我将使用
base64
<代码>sha

也适用于我的用例。