在groovy中解析嵌套的json对象
我有一个json文件,其中包含按城市分组的联系人信息。我想解析json并创建一个名称和数字列表,但在摆弄了一个小时左右之后,我无法在groovy中使用它在groovy中解析嵌套的json对象,json,groovy,Json,Groovy,我有一个json文件,其中包含按城市分组的联系人信息。我想解析json并创建一个名称和数字列表,但在摆弄了一个小时左右之后,我无法在groovy中使用它 def json = '''{ "date":"2018-01-04T22:01:02.2125", "boston": [ { "name":"bob", "phone":"242 123123", "ext":"12", "email":"bob@boston.com"
def json = '''{
"date":"2018-01-04T22:01:02.2125",
"boston": [
{
"name":"bob",
"phone":"242 123123",
"ext":"12",
"email":"bob@boston.com"
},
{
"name":"alice",
"phone":"212-123-345",
"ext":"1",
"email":"alice@boston.com"
}
],
"chicago": [
{
"name":"charlie",
"phone":"313-232-545",
"ext":"14",
"email":"charlie@chicago.com"
},
{
"name":"denise",
"phone":"414-123-546",
"ext":"9",
"email":"denise@chicago.com"
}
]
}'''
我尝试了以下主题的一些变体,但到目前为止都失败了
parsedjson = slurper.parseText(json)
phonelist = []
parsedjson.each{phonelist.add([it['name'],it['phone']])}
使用json很棘手,因为您需要查找列表中的值。。。您可以使用
findAll
实现这一点,因此给定json:
def json = '''{
"date":"2018-01-04T22:01:02.2125",
"boston": [
{
"name":"bob",
"phone":"242 123123",
"ext":"12",
"email":"bob@boston.com"
},
{
"name":"alice",
"phone":"212-123-345",
"ext":"1",
"email":"alice@boston.com"
}
],
"chicago": [
{
"name":"charlie",
"phone":"313-232-545",
"ext":"14",
"email":"charlie@chicago.com"
},
{
"name":"denise",
"phone":"414-123-546",
"ext":"9",
"email":"denise@chicago.com"
}
]
}'''
您可以导入JsonSlurper并像当前一样解析json:
import groovy.json.JsonSlurper
def parsedjson = new JsonSlurper().parseText(json)
然后,
明亮的非常感谢。我在我的问题中添加了你的漂亮json,你介意从你的答案中删除它吗?只是为了让答案在howdoi和helpmecode中看起来更好。干杯!
def result = parsedjson.findAll { it.value instanceof List } // Find all entries with a list value
.values() // Get all the lists
.flatten() // Merge them into a single list
.collect { [it.name, it.phone] } // grab the name and phone for each