kotlin-比较并组合Hashmap的键和值

我有两个Hashmap

hashMap1 : HashMap<String, MutableList<String>> = {ab=["hello", "how", "are", "you"], cd=["my", "world"], ef = ["life", "is", "nice"]}
hashMap2 : HashMap<String, MutableList<String>> = {ab=["how", "you", "in", "life"], ef = ["nice", "to"], gd = ["fun"]}

---

如何获得此输出？

根据您描述的输入和输出猜测，我创建了此测试用例，适用于您的示例：

@Test
fun `should return map with key-value pairs of only matching value strings`() {
    val hashMap1 = hashMapOf(
        "ab" to listOf("hello", "how", "are", "you"),
        "cd" to listOf("my", "world"),
        "ef" to listOf("life", "is", "nice")
    )
    val hashMap2 = hashMapOf(
        "ab" to listOf("how", "you", "in", "life"),
        "ef" to listOf("nice", "to"),
        "gd" to listOf("fun")
    )

    val result = hashMap1
            .filter { (key, _) -> hashMap2.containsKey(key) }
            .mapValues { (key, value) -> hashMap2.getValue(key).filter { it in value } }
            .filter { (_, value) -> value.isNotEmpty() }

    assertThat(result).isEqualTo(
        hashMapOf(
            "ab" to listOf("how", "you"),
            "ef" to listOf("nice")
        )
    )
}

---

让我们知道您尝试了什么请为您的示例添加有效的kotlin代码谢谢您的帮助。

@Test
fun `should return map with key-value pairs of only matching value strings`() {
    val hashMap1 = hashMapOf(
        "ab" to listOf("hello", "how", "are", "you"),
        "cd" to listOf("my", "world"),
        "ef" to listOf("life", "is", "nice")
    )
    val hashMap2 = hashMapOf(
        "ab" to listOf("how", "you", "in", "life"),
        "ef" to listOf("nice", "to"),
        "gd" to listOf("fun")
    )

    val result = hashMap1
            .filter { (key, _) -> hashMap2.containsKey(key) }
            .mapValues { (key, value) -> hashMap2.getValue(key).filter { it in value } }
            .filter { (_, value) -> value.isNotEmpty() }

    assertThat(result).isEqualTo(
        hashMapOf(
            "ab" to listOf("how", "you"),
            "ef" to listOf("nice")
        )
    )
}