Matlab 生成给定PDF的随机值

Matlab 生成给定PDF的随机值,matlab,random,Matlab,Random,我必须根据确定的概率密度函数(截断拉普拉斯函数)生成随机值: Sigma_Phi=1; B=1/(1-exp(-sqrt(2)*pi/Sigma_-Phi)); φ=-60:0.001:60; 对于iter=1:长度(φ) 如果φ(iter)=0 P(iter)=(B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_-Phi))/(sqrt(2)*Sigma_-Phi)); elseif Phi(iter)>=-pi&&Phi(iter)以下是一个简单的通用解决方案: 再现性

我必须根据确定的概率密度函数(截断拉普拉斯函数)生成随机值:

Sigma_Phi=1;
B=1/(1-exp(-sqrt(2)*pi/Sigma_-Phi));
φ=-60:0.001:60;
对于iter=1:长度(φ)
如果φ(iter)=0
P(iter)=(B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_-Phi))/(sqrt(2)*Sigma_-Phi));

elseif Phi(iter)>=-pi&&Phi(iter)以下是一个简单的通用解决方案:

再现性的
%
rng(333)
σφ=1;
B=1/(1-exp(-sqrt(2)*pi/Sigma_-Phi));
φ=-10:0.001:10;
P=nan(长度(φ),1);
对于iter=1:长度(φ)
如果φ(iter)=0
P(iter)=(B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_-Phi))/(sqrt(2)*Sigma_-Phi));
elseif-Phi(iter)>=-pi&&Phi(iter)=-pi;
cdf=cdf(idx_mid);
φ=φ(idx_mid);
P=P(idx_mid);
%所需的随机抽取次数
n=1e4;
%从[0,1]生成均匀分布的随机数
r=rand(n,1);
%从所需的pdf生成随机数;逆变换采样
laplrnd=interp1(cdf,Phi,r);
%验证图
[f,x]=hist(laplrnd,100);
横杆(x,f/trapz(x,f))
等等
绘图(φ、P、红色、线宽、1.2)
图例(‘随机值直方图’、‘分析pdf’)

    Sigma_Phi = 1;
B = 1/(1-exp(-sqrt(2)*pi/Sigma_Phi));
Phi = -60:0.001:60;

for iter=1:length(Phi)
    if Phi(iter) < pi && Phi(iter)>=0
        P(iter) = ((B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_Phi)))/(sqrt(2)*Sigma_Phi));
    elseif Phi(iter) >= -pi && Phi(iter)<=0
        P(iter) = ((B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_Phi)))/(sqrt(2)*Sigma_Phi));
    else
        P(iter)=0;
    end
end
% for reproducibility
rng(333) 

Sigma_Phi = 1;
B = 1/(1-exp(-sqrt(2)*pi/Sigma_Phi));
Phi = -10:0.001:10;

P = nan(length(Phi),1);
for iter=1:length(Phi)
    if Phi(iter) < pi && Phi(iter)>=0
        P(iter) = ((B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_Phi)))/(sqrt(2)*Sigma_Phi));
    elseif Phi(iter) >= -pi && Phi(iter)<=0
        P(iter) = ((B*exp(-abs(sqrt(2)*Phi(iter)/Sigma_Phi)))/(sqrt(2)*Sigma_Phi));
    else
        P(iter)=0;
    end
end

% create cdf
cdf         = cumtrapz(Phi, P);

% keep only the unique values: needed for interpolation
idx_mid = (Phi < pi) & (Phi >= -pi);
cdf = cdf(idx_mid);
Phi = Phi(idx_mid);
P   = P(idx_mid);

% number of required random draws
n = 1e4;
% generate uniformly distributed random numbers from [0,1]
r = rand(n,1);

% generate random numbers from the desired pdf; inverse transform sampling
laplrnd = interp1(cdf, Phi, r);

% Verfication plot
[f,x] = hist(laplrnd,100);

bar(x,f/trapz(x,f))
hold on
plot(Phi, P, 'red', 'Linewidth', 1.2)
legend('histogram from random values', 'analytical pdf')