Mustache 忽略从胡须模板中的父上下文继承的属性
在小胡子模板中,如何忽略从父上下文继承的属性?例如,将此视为模板数据:Mustache 忽略从胡须模板中的父上下文继承的属性,mustache,Mustache,在小胡子模板中,如何忽略从父上下文继承的属性?例如,将此视为模板数据: { "name": "Alice", "age": 45, "children": [ { "name": "Bob", "age": 11 }, { "name": "Clare" } ] } { "name": "Alice", "age": 45, "children": [ { "name": "Bo
{
"name": "Alice",
"age": 45,
"children": [
{
"name": "Bob",
"age": 11
},
{
"name": "Clare"
}
]
}
{
"name": "Alice",
"age": 45,
"children": [
{
"name": "Bob",
"age": 11
},
{
"name": "Clare",
"age": null
}
]
}
我们可以使用以下模板呈现数据:
<p>{{name}} (age {{age}})</p>
<ul>
{{#children}}
<li>{{name}} (age {{age}})</li>
{{/children}}
</ul>
{{name}(年龄{{age})
{{{儿童}
- {{name}(年龄{{age})
{{/儿童}
我们将获得以下HTML:
<p>Alice (age 45)</p>
<ul>
<li>Bob (age 11)</li>
<li>Clare (age 45)</li>
</ul>
爱丽丝(45岁)
- 鲍勃(11岁)
- 克莱尔(45岁)
如果
age
属性来自当前上下文,而不是从父上下文继承,如何才能显示该属性?一种可能的解决方案是确保模板数据中存在空值:
{
"name": "Alice",
"age": 45,
"children": [
{
"name": "Bob",
"age": 11
},
{
"name": "Clare"
}
]
}
{
"name": "Alice",
"age": 45,
"children": [
{
"name": "Bob",
"age": 11
},
{
"name": "Clare",
"age": null
}
]
}