Mysql 使用SQL从行中的值创建列

Mysql 使用SQL从行中的值创建列,mysql,sql,pivot-table,entity-attribute-value,Mysql,Sql,Pivot Table,Entity Attribute Value,有人能帮我用sql连接两个表吗?连接后的行应显示为列,如下所示 我有两张桌子T1和T2 T1 ------------ Id. Name date -------------- 1 AAA 2019-05-06 2 BBB 2019-05-06 T2 --------------- Id. attr_name. attr_value. date -------------------- 1 . PP0 8 2019-05-06

有人能帮我用sql连接两个表吗?连接后的行应显示为列,如下所示

我有两张桌子T1和T2

T1
------------
Id.  Name  date
--------------
1    AAA    2019-05-06
2    BBB    2019-05-06



T2
---------------
Id.  attr_name. attr_value. date
--------------------
1 .   PP0         8       2019-05-06    
1 .   PD0        125.00     2019-05-06
1     PP1         2         2019-05-06
1     PD1        150.00      2019-05-06
3     PP0         5         2019-05-06
3     PD1        50.00      2019-05-06

当有PP0时,将有相应的PD0

My output should be
---------------------
Id    Name       attr_pp_name     attr_pp_value.  attr_pd_name     attr_pd_value
1     AAA          PP0                  8               PD0          125.00
1.    AAA          PP1                  2               PD1          150.00
我尝试了我的问题如下

select t.Id, t.name ea.attr_name ,ea.attr_value, ea1.attr_name, ea1.attr_value from T1 t
INNER JOIN T2 ea ON t.id = ea.id AND ea.attr_name IN ('PP0', 'PP1')
INNER JOIN T2 ea1 ON t.id = ea.id AND ea.attr_name IN ('PD0', 'PD1');
但是上面的查询给出了重复的结果

Id    Name       attr_pp_name     attr_pp_value.  attr_pd_name     attr_pd_value
1     AAA          PP0                  8               PD0          125.00
1.    AAA          PP1                  2               PD1          150.00
1     AAA          PP0                  2               PD1          150.00
1.    AAA          PP1                  8               PD0          125.00


在MySQL 8+中,您可以使用窗口函数枚举属性值,然后聚合:

select t.*,
       max(case when ea.attr_name like 'PP%' then ea.attr_name end),
       max(case when ea.attr_name like 'PP%' then ea.attr_value end),
       max(case when ea.attr_name like 'PD%' then ea.attr_name end),
       max(case when ea.attr_name like 'PD%' then ea.attr_value end)
from T1 t join
     (select ea.*,
             row_number() over (partition by ea.id, left(ea.attr_name, 2) order by ea.id) as seqnum
      from t2 ea
     ) ea
     on ea.id = t.id
group by t.id, ea.seqnum;
编辑:

在早期版本中实现这一点的一种方法是使用变量:

select t.*,
       max(case when ea.attr_name like 'PP%' then ea.attr_name end),
       max(case when ea.attr_name like 'PP%' then ea.attr_value end),
       max(case when ea.attr_name like 'PD%' then ea.attr_name end),
       max(case when ea.attr_name like 'PD%' then ea.attr_value end)
from T1 t join
     (select ea.*,
             (@rn := if(@ida = concat_ws(':', ea.id, left(ea.attr_name, 2)), @rn + 1,
                        if(@ida := concat_ws(':', ea.id, left(ea.attr_name, 2)), 1, 1)
                       )
             ) as seqnum
      from (select ea.*
            from t2 ea
            order by ea.id, left(ea.attr_name, 2)
           ) ea cross join
           (select @ida := '', @rn := 0) params
     ) ea
     on ea.id = t.id
group by t.id, ea.seqnum;

那么你想要的结果是什么呢?它们不是真正的重复,是吗?让我重新表述我的问题。我的意思是PP0应该有相应的PD0值。但是我的查询PP0有PD1行,这不是必需的。谢谢回复,我不能使用mysql 8+。是否可以在不使用窗口函数的情况下修改此查询?