如何将mysql表行转换为列
以下是我当前的mysql表的外观:如何将mysql表行转换为列,mysql,sql,pivot,Mysql,Sql,Pivot,以下是我当前的mysql表的外观: PunchID EmpID PunchEvent PunchDateTime 1 0456 clockin 5/14/2013 8:36:26 AM 48 0456 breakout 5/14/2013 12:01:29 PM 53 0456 breakin 5/14/2013 12:28:31 PM 54 0456 clockout 5/14/2013 2:2
PunchID EmpID PunchEvent PunchDateTime
1 0456 clockin 5/14/2013 8:36:26 AM
48 0456 breakout 5/14/2013 12:01:29 PM
53 0456 breakin 5/14/2013 12:28:31 PM
54 0456 clockout 5/14/2013 2:28:33 PM
57 0456 clockin 5/15/2013 7:38:34 AM
58 0456 breakout 5/15/2013 7:38:39 AM
59 0456 breakin 5/15/2013 7:38:41 AM
60 0456 clockout 5/15/2013 7:38:42 AM
现在,我想返回一个结果集,该结果集根据一周中的某一天进行分组,如下所示:
Day ClockIn BreakOut BreakIn ClockOut
Tuesday 8:36:26 AM 12:01:29 PM 12:28:31 PM 2:28:33 PM
Wednesday 7:38:34 AM etc, etc...
这是我目前的问题。但它每天只会返回第一拳
SELECT DATE_FORMAT(PunchDateTime, '%W') as day, PunchEvent, DATE_FORMAT(PunchDateTime, '%l:%m:%s %p') as time FROM timeclock_punchlog WHERE EmpID = '0456' GROUP BY DATE(PunchDateTime) ORDER BY PunchDateTime ASC;
有人能帮我吗?
谢谢
迈克
╔═══════════╦═════════════╦═════════════╦═════════════╦═════════════╗
║ DAY ║ CLOCKIN ║ BREAKOUT ║ BREAKIN ║ CLOCKOUT ║
╠═══════════╬═════════════╬═════════════╬═════════════╬═════════════╣
║ Tuesday ║ 08:36:26 AM ║ 12:01:29 PM ║ 12:28:31 PM ║ 02:28:33 PM ║
║ Wednesday ║ 07:38:34 AM ║ 07:38:39 AM ║ 07:38:41 AM ║ 07:38:42 AM ║
╚═══════════╩═════════════╩═════════════╩═════════════╩═════════════╝
[ [ [1]: [2]:我猜如果每天有多个PunchEvent,这就不起作用了?你说的
每天有多个PunchEvent是什么意思?
?如果我周二有3个'breakin'和3个'breakout',它会显示出来吗?如果你有这些记录,输出会是什么样子?嗯,我想列的数量会是任意的这可能是MySQL不可能做到的。
╔═══════════╦═════════════╦═════════════╦═════════════╦═════════════╗
║ DAY ║ CLOCKIN ║ BREAKOUT ║ BREAKIN ║ CLOCKOUT ║
╠═══════════╬═════════════╬═════════════╬═════════════╬═════════════╣
║ Tuesday ║ 08:36:26 AM ║ 12:01:29 PM ║ 12:28:31 PM ║ 02:28:33 PM ║
║ Wednesday ║ 07:38:34 AM ║ 07:38:39 AM ║ 07:38:41 AM ║ 07:38:42 AM ║
╚═══════════╩═════════════╩═════════════╩═════════════╩═════════════╝