Mysql 5.7-从子选择中获取多个值

在下面的查询中，我正在“加入”另一个表，其中

I.isPrimary>0

，如果所有

I.isPrimary

都是

0

，我只得到第一个结果

查询的结果集与预期一致，但我希望从每个子选择中带来更多值。
我收到错误：

SQL错误（1241）：操作数应包含1列

如何重写此查询以从每个子选择中获得更多结果

谢谢

-- borrowed from https://stackoverflow.com/q/7745609/808921

CREATE TABLE IF NOT EXISTS `ResearchEntity` (
  `id` int(6) unsigned NOT NULL,
  `name`  varchar(200) NOT NULL,
  PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;

INSERT INTO `ResearchEntity` (`id`, `name`) VALUES
  ('1', 'one'),
  ('2', 'two'),
  ('3', 'three');
  
CREATE TABLE IF NOT EXISTS `ProfileImageEntity` (
  `id` int(6) unsigned NOT NULL,
  `isPrimary` int(1) unsigned NOT NULL,
  `value` varchar(200) NOT NULL,
  `researchId` int(2) unsigned NOT NULL,
  PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;

INSERT INTO `ProfileImageEntity` (`id`,`isPrimary`, `value`,`researchId`) VALUES
  ('1', 0, 'not primary',1),
  ('2', 0, 'not primary',1),
  ('3', 1, 'primary!!!',1),
  
  ('4', 0, 'primary!!!',2),
  ('5', 0, 'not primary',2),
  ('6', 0, 'not primary',2)
  
  ;


CREATE TABLE IF NOT EXISTS `UserNameEntity` (
  `id` int(6) unsigned NOT NULL,
  `isPrimary` int(1) unsigned NOT NULL,
  `value` varchar(200) NOT NULL,
  `researchId` int(2) unsigned NOT NULL,
  PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;

INSERT INTO `UserNameEntity` (`id`,`isPrimary`, `value`,`researchId`) VALUES
  ('1', 0, 'first one, should be returned',1),
  ('2', 0, 'not primary',1),
  ('3', 0, 'primary',1),
  
  ('4', 1, 'primary',3),
  ('5', 0, 'not primary',3),
  ('6', 0, 'not primary',3);

SQL小提琴 :

尝试左连接

SELECT r.*,i.id FROM ResearchEntity r left join ProfileImageEntity i on r.id = i.researchId 
ORDER BY  i.isPrimary,i.id DESC;

---

你只需要离开加入2次

SELECT r.*,i.id,j.id FROM ResearchEntity r left join ProfileImageEntity i on r.id = i.researchId left join UserNameEntity j on r.id=j.researchId  ORDER BY  i.isPrimary,i.id DESC;

---

我从您的问题和评论中了解到，您希望从子查询中获得更多的列，这是不可能的。因此，请尝试以下查询：

在MySql 8中这很容易，但您使用的是MySql 5.7，其中有点棘手，因此请尝试以下方法：

select 
t1.*, 
t2.id AS primaryImageId, 
t2.value AS primaryImageValue, 
t3.id AS primaryUserId,
t3.value AS primaryUserValue
from ResearchEntity t1 

left join ( 

  SELECT    *,
              IF(researchId=@last,@_seq:=@_seq+1,@_seq:=1) AS rn,
              @last:=researchId
    FROM      ProfileImageEntity , (SELECT @_seq:=1, @last:=0) r
    ORDER BY  researchId,isPrimary DESC, id ASC 
   
   ) t2 on t1.id=t2.researchId and t2.rn=1

left join (
  SELECT    *,
              IF(researchId=@last,@_seq:=@_seq+1,@_seq:=1) AS rn,
              @last:=researchId
    FROM      UserNameEntity , (SELECT @_seq:=1, @last:=0) r
    ORDER BY  researchId,isPrimary DESC, id ASC 
   ) t3 on t1.id=t3.researchId and t3.rn=1
   
   order by t1.id

在MySql 8中使用

row\u number（）

---

请参见@草莓-添加了您希望从样本数据中获得的输出？@AkhileshMishra-表

ProfileImageEntity

和

UserNameEntity

有一列

值，我想将其添加到结果中
primaryImageId、primaryImageValue primaryUserNameId、primaryUserNameValue
感谢我从您的问题中了解到的内容，并对您希望从子查询中获得更多列的内容进行注释，这是不可能的。这不能用于像我的queryBingo这样的多个联接表。谢谢在mysql8中，这如何更简单？再次感谢！我已经添加了MySql 8的查询。
select 
t1.*, 
t2.id AS primaryImageId, 
t2.value AS primaryImageValue, 
t3.id AS primaryUserId,
t3.value AS primaryUserValue
from ResearchEntity t1 

left join ( 

  SELECT    *,
              IF(researchId=@last,@_seq:=@_seq+1,@_seq:=1) AS rn,
              @last:=researchId
    FROM      ProfileImageEntity , (SELECT @_seq:=1, @last:=0) r
    ORDER BY  researchId,isPrimary DESC, id ASC 
   
   ) t2 on t1.id=t2.researchId and t2.rn=1

left join (
  SELECT    *,
              IF(researchId=@last,@_seq:=@_seq+1,@_seq:=1) AS rn,
              @last:=researchId
    FROM      UserNameEntity , (SELECT @_seq:=1, @last:=0) r
    ORDER BY  researchId,isPrimary DESC, id ASC 
   ) t3 on t1.id=t3.researchId and t3.rn=1
   
   order by t1.id


with cte as (
SELECT  *,
row_number() over (partition by researchId ORDER BY isPrimary DESC, id ASC) rn
FROM ProfileImageEntity
),

cte1 as (
sELECT  *,
row_number() over (partition by researchId ORDER BY  isPrimary DESC, id ASC) rn
FROM UserNameEntity
)

select 
t1.*, 
t2.id AS primaryImageId, 
t2.value AS primaryImageValue, 
t3.id AS primaryUserId,
t3.value AS primaryUserValue
from ResearchEntity t1 left join cte t2 on t1.id=t2.researchId and t2.rn=1

left join cte1 t3 on t1.id=t3.researchId and t3.rn=1