你将如何整理这个Mysql逻辑

我用它来显示每日基本数据。 假设一个人每天吃3次早、中、午。所以我像这样输入数据

Table: table
--------------------------------------------------------------------
| manId(AI)(PK) |  date | schedules | amount | blah | [....]
--------------------------------------------------------------------

 102 - 01/01/2016 - 0.5 KG (morning time data)
 102 - 01/01/2016 - 0.5 KG (noon time data)
 102 - 01/01/2016 - 0.5 KG (after_noon time data)
 103 - 01/01/2016 - 0.5 KG (morning time data)

102 - 01/01/2016 - 1.5 KG (Sum all schedules)
103 - 02/01/2016 - 1.5 KG (Sum all schedules)
104 - 03/01/2016 - 1.5 KG (Sum all schedules)

当我查询显示morris图表数据时，它会像这样显示每个数据

Table: table
--------------------------------------------------------------------
| manId(AI)(PK) |  date | schedules | amount | blah | [....]
--------------------------------------------------------------------

 102 - 01/01/2016 - 0.5 KG (morning time data)
 102 - 01/01/2016 - 0.5 KG (noon time data)
 102 - 01/01/2016 - 0.5 KG (after_noon time data)
 103 - 01/01/2016 - 0.5 KG (morning time data)

102 - 01/01/2016 - 1.5 KG (Sum all schedules)
103 - 02/01/2016 - 1.5 KG (Sum all schedules)
104 - 03/01/2016 - 1.5 KG (Sum all schedules)

我想做的是，每天都会像这样展示

Table: table
--------------------------------------------------------------------
| manId(AI)(PK) |  date | schedules | amount | blah | [....]
--------------------------------------------------------------------

 102 - 01/01/2016 - 0.5 KG (morning time data)
 102 - 01/01/2016 - 0.5 KG (noon time data)
 102 - 01/01/2016 - 0.5 KG (after_noon time data)
 103 - 01/01/2016 - 0.5 KG (morning time data)

102 - 01/01/2016 - 1.5 KG (Sum all schedules)
103 - 02/01/2016 - 1.5 KG (Sum all schedules)
104 - 03/01/2016 - 1.5 KG (Sum all schedules)

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使用

date

列上的

groupby

和

sum

所有值

SELECT id,date,SUM(amount)
FROM table_name
GROUP BY date;