Mysql 从多个表检索数据的SQL查询

这是正确的答案：

SELECT 
    p.product_name,
    coalesce((sum((i.time_paid is null and i.time_canceled is null and i.time_refunded is null) * it.line_total_price)), 0) due,
    coalesce((sum((i.time_paid is not null) * it.line_total_price)), 0) paid,
    coalesce((sum((i.time_canceled is not null) * it.line_total_price)), 0) canceled,
    coalesce((sum((i.time_refunded is not null) * it.line_total_price)), 0) refunded
FROM
    PRODUCT p
LEFT JOIN invoice_item it ON p.id = it.product_id
LEFT JOIN invoice i ON it.invoice_id = i.id
GROUP BY
    p.id, p.product_description

我所要添加的当前代码就是添加null和*total_price

---

谢谢

我认为您需要条件聚合。逻辑没有很好地指定（特别是对于

due

列），但我认为这应该接近您想要的：

select 
    p.description,
    coalesce(sum((i.time_paid is null and i.time_cancelled is null and i.time_refund is null) * ii.line_total_price)), 0) due,
    coalesce(sum((i.time_paid is not null) * ii.line_total_price)), 0) paid,
    coalesce(sum((i.time_cancelled is not null) * ii.line_total_price)), 0) cancelled,
    coalesce(sum((i.time_refunded is not null) * ii.line_total_price)), 0) refunded
from products p
left join invoice_item ii on ii.product_id = p.id
left join invoices i on i.id = ii.invoice_id
group by p.id, p.description

---

这应该给你一个如何做的想法。您可能需要摆弄CASE语句内部的逻辑，以便它是正确的，但这只是一个开始：

DROP TABLE invoice_item;
DROP TABLE product;
DROP TABLE invoice;

CREATE TABLE product (
id int,
sku varchar(32),
product_name varchar(128),
product_description text,
current_price decimal(8,2),
quantity_in_stock int
);

CREATE TABLE invoice (
id int,
invoice_number varchar(255),
customer_id int,
user_account_id int, 
total_price decimal(8,2),
time_issued DATETIME,
time_due DATETIME,
time_paid DATETIME,
time_canceled DATETIME,
time_refunded DATETIME
);

CREATE TABLE invoice_item (
  id int,
  invoice_id int,
  product_id int,
  quantity int,
  price decimal(8,2),
  line_total_price decimal(8,2)
);


insert into product (id,sku,product_name,product_description,current_price,quantity_in_stock) VALUES
(1,10,'Product 1','Description for Product 1',65,122),
(2,11,'Product 2','Description for Product 2',98,51),
(3,12,'Product 3','Description for Product 3',45,34),
(4,13,'Product 4','Description for Product 4',25,393),
(5,14,'Product 5','Description for Product 5',95,74),
(6,15,'Product 6','Description for Product 6',45,40),
(7,16,'Product 7','Description for Product 7',62,154),
(8,17,'Product 8','Description for Product 8',80,0),
(9,18,'Product 9','Description for Product 9',20,281),
(10,19,'Product 10','Description for Product 10',170,0);


INSERT INTO invoice (id, invoice_number,customer_id,user_account_id, total_price,time_issued,time_due,time_paid) VALUES
(1,'800c8d2fc967fe',7,4,1436,'2019-07-20 15:05:07','2019-07-27 15:05:07','2019-07-25 21:24:12'),
(2,'b27502b9f81e9d',9,2,1000,'2019-07-20 15:07:11','2019-07-27 15:07:11','2019-07-20 15:10:32'),
(3,'6b6bcfd3dfcd9b',3,2,360,'2019-07-20 15:06:15','2019-07-27 15:06:15','2019-07-31 21:22:11');

INSERT INTO invoice (id, invoice_number,customer_id,user_account_id, total_price,time_issued,time_due) VALUES
(4,'2196vac9a0120ad',5,2,1675,'2019-07-20 15:06:34','2019-07-27 15:06:34');

INSERT INTO invoice (id, invoice_number,customer_id,user_account_id, total_price,time_issued,time_due,time_paid,time_canceled) VALUES
(5,'4440d698878af70',6,2,9500,'2019-07-20 15:06:42','2019-07-27 15:06:42',NULL,'2019-07-22 11:17:02');

INSERT INTO invoice (id, invoice_number,customer_id,user_account_id, total_price,time_issued,time_due,time_paid,time_canceled,time_refunded) VALUES
(6,'4320bcab8fc4322',4,2,150,'2019-07-20 15:08:15','2019-07-27 15:08:15','2019-07-27 13:42:45',NULL,'2019-07-27 14:11:20');

INSERT INTO invoice_item
(id,invoice_id,product_id,quantity,price,line_total_price) VALUES
(1,1,1,20,65,1300),
(2,1,7,2,62,136),
(3,1,5,10,100,1000),
(4,3,10,2,180,360),
(5,4,1,5,65,325),
(6,4,2,10,95,950),
(7,4,5,4,100,400),
(8,5,10,100,95,9500),
(9,6,4,6,25,150);


  SELECT 
    p.product_name,
    (COALESCE (SUM(CASE WHEN i.time_paid is null and i.time_canceled is null and i.time_refunded is null IS NOT NULL THEN it.quantity * it.price ELSE 0 END ),0)) as due,
    (COALESCE (SUM(CASE WHEN i.time_paid IS NOT NULL THEN it.quantity * it.price ELSE 0 END ),0)) as paid,
    (COALESCE (SUM(CASE WHEN i.time_canceled IS NOT NULL THEN it.quantity * it.price ELSE 0 END ),0)) as canceled,
    (COALESCE (SUM(CASE WHEN i.time_refunded IS NOT NULL THEN it.quantity * it.price ELSE 0 END ),0)) as refunded
FROM
    PRODUCT p
LEFT OUTER JOIN invoice_item it ON p.id = it.product_id
LEFT OUTER JOIN invoice i ON it.invoice_id = i.id
GROUP BY 
    product_name
ORDER BY 
    p.id ASC

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您当前的输出是什么，为什么是错误的，以及您在这里期望的输出是什么？您缺少期望的结果。@TimBiegeleisen我当前的输出都是带有时间戳的产品，我想显示到期、已付款、已取消和退款的时间戳的金额。为什么数据看起来与表定义不同？“到期、已付款，取消并退款”-您需要告诉我们@uzjab的逻辑。你有什么理由接受另一个答案吗？这个答案在25分钟后发布，其逻辑与我的相似。很抱歉，我没有点击另一个帖子的接受答案，而不是答案是有用的。再次非常感谢你的帮助，我想我的工作，并在它的所有设置。当我用测试数据运行你的时，它失败了。如果我们期望人们在提问时提供几乎可以工作的代码，那么我们不也应该期望anwers做出类似的努力吗？