将多行合并为一行并放入表MySQL中

对不起我的英语）我有三张桌子。下一种类型：

表1-用户

--------------------------------
| id     | email    | password |
--------------------------------
| 1      | 1        | 3        |
| 2      | 1        | 4        |
| 3      | 1        | 3        |
| 4      | 1        | 4        |
| 5      | 2        | 3        |
| 6      | 2        | 4        |
| 7      | 2        | 3        |
| 8      | 2        | 4        |
--------------------------------

表2：分数

---------------------------
 id     | idUser    | nameScore|
--------------------------------
| 1      | 1        | df       |
| 2      | 1        | sa       |
| 3      | 1        | as       |
| 4      | 1        | 4        |
| 5      | 2        | 3        |
| 6      | 2        | 4        |
| 7      | 2        | 3        |
| 8      | 2        | 4        |
-------------------------------|

表3：付款

--------------------------------------------------
| id     | idScorePayer   |idScorePayee|  money
--------------------------------------------------
| 1      | 1              |    2       |   1000
| 2      | 2              |    4       |   700
| 3      | 3              |    1       |   1500
| 4      | 4              |    3       |   9000
---------------------------------------------------

我试图输出的内容：

-----------------------------------------------
| id     | emailPayer   | emailPayee      | money
-----------------------------------------------
| 1      | yellow@      | cookies@        |
| 2      | yellow@      | milk@           |
| 3      | yellow@      | cookies@        |
| 4      | yellow@      | milk@           |
| 5      | blue@        | cookies@        |
| 6      | blue@        | milk@           |
| 7      | blue@        | cookies@        |
| 8      | blue@        | milk@           |
-----------------------------------------------

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我没有MySQL实例可供测试，我猜是在电子邮件表上，但我认为应该是这样的：

SELECT
   users.id,
   email1.email_name "emailPayer",
   email2.email_addr "emailPayee",
   payment.money
FROM
   users
     JOIN scores ON (users.id = scores.idUser)
     JOIN payment ON (scores.id = payment.idScorePayer)
     JOIN email email1 ON (scores.idScorePayer = email.id)
     JOIN email email2 ON (scores.idSCorePayee = email.id)

---

下面的查询应该有效：

select u1.email as emailPayer, u2.email as emailPayee, amount
from users u1 join scores s1 on u1.id = s1.idUser
join payment on s1.id = payment.idScorePayer
join scores s2 on payment.idScorePayee = s2.idUser
join users u2 on u2.id = s2.idUser

---

你能把你的桌子安排得好一点吗？你的问题不清楚，从哪里可以得到黄色、蓝色、饼干、牛奶？？请阅读，这里是一个学习如何提高问题质量和获得更好答案的好地方。电子邮件表未显示