Node.js 可能有人帮我传递URL作为参数吗

我有两个节点文件，我需要知道如何打开第二个文件作为参数传递第一个文件的url

var express = require('express');
var request = require('request');
var app     = express();
var file2 = require('./file2'); //import file2 
var arr2 = [];
app.get('/', function(req, res,body){   
    var queryParam = req.query;
    var url = queryParam.website;
    file2.request(url,....) ///fill what you need 
})
app.listen('3000')
console.log('Web Scrape happens on port 3000');
exports = module.exports = app;

服务器文件（第一个文件）

（第二个文件）从网站中提取链接的文件

var request = require('request');
var cheerio = require('cheerio');
request(url , function(err,resp,body){
    $ = cheerio.load(body);
    links = $('a');
    $(links).each(function(i,link){
        console.log(url+$(link).attr('href'));
    }
   )
})

问题是如何将url从第一个文件传递到第二个文件。在节点js中是否有可能将ur作为参数传递？

试试这个

（第二档）

第一档

var express = require('express');
var request = require('request');
var app     = express();
var file2 = require('./file2'); //import file2 
var arr2 = [];
app.get('/', function(req, res,body){   
    var queryParam = req.query;
    var url = queryParam.website;
    file2.request(url,....) ///fill what you need 
})
app.listen('3000')
console.log('Web Scrape happens on port 3000');
exports = module.exports = app;

---

导出第二个模块中的函数，然后调用该函数并向其传递URL。

var express = require('express');
var request = require('request');
var app     = express();
var file2 = require('./file2'); //import file2 
var arr2 = [];
app.get('/', function(req, res,body){   
    var queryParam = req.query;
    var url = queryParam.website;
    file2.request(url,....) ///fill what you need 
})
app.listen('3000')
console.log('Web Scrape happens on port 3000');
exports = module.exports = app;