Objective c 使用搜索栏搜索tableview时获取NCFString错误

我得到了一个从json字符串解析的表视图。一切正常。如果我要在搜索栏中键入一个字符，我会得到这个错误

”-[\u NSCFString CountByEnumerating with State:objects:count:]：发送到实例0x1d52ac50的无法识别的选择器“

下面是代码。下面的变量名数据是NSMUTABLEARRY。你们能帮我一下吗

- (BOOL)searchDisplayController:(UISearchDisplayController *)controllershouldReloadTableForSearchString:(NSString *)searchString
    {
[searchData removeAllObjects];

NSArray *group;
for(group in nameData)
{
    NSLog(@"wat am i doing here:%@",group);
    NSMutableArray *newGroup = [[NSMutableArray alloc] init];
    NSString *element;

    for(element in group)
    {
        NSRange range = [element rangeOfString:searchString options:NSCaseInsensitiveSearch];

        if (range.length > 0) {
            [newGroup addObject:element];
        }
    }

    if ([newGroup count] > 0) {
        [searchData addObject:newGroup];
    }

}

return YES;
 }

---

请查看此代码

 - (BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString
{
    NSMutableArray *array=[[NSMutableArray alloc]init];
    NSDictionary *naming= [self.friendsDictionary objectForKey:@"data"];
    NSLog(@"ggg %@",[self.friendsDictionary objectForKey:@"data"]);
    for(int i =0 ; i< [[self.friendsDictionary objectForKey:@"data"] count]; i++){
        [array addObject:[[[self.friendsDictionary objectForKey:@"data"] objectAtIndex:i] objectForKey:@"name"]];
    }
    NSLog(@"Array %@", array);

    if(self.searchDisplayController.searchBar.text.length>0) 
    {
        NSString *strSearchText = self.searchDisplayController.searchBar.text;
        NSMutableArray *group = [[NSMutableArray alloc]init];
        for (int i=0; i<array.count; i++) {

            NSString *strData = [array objectAtIndex:i]; 
              NSLog(@"string Data:%@",strData);
            NSRange rng = [strData rangeOfString:strSearchText options:NSCaseInsensitiveSearch];
            if(rng.location != NSNotFound)
            {
                if(rng.location== 0)//that is we are checking only the start of the names.
                {
                    [group addObject:strData]; 
                }
            }
        }
        if ([group count] > 0) 
        {
    searchData = [[NSMutableArray alloc] init];
            [searchData addObjectsFromArray:group];
            NSLog(@"Sear %@", searchData);

        }
    } 
    return YES;
  }

-（BOOL）searchDisplayController:（UISearchDisplayController*）控制器应重新加载TableForSearchString:（NSString*）searchString
{
NSMUTABLEARRY*array=[[NSMUTABLEARRY alloc]init]；
NSDictionary*命名=[self.friendsDictionary objectForKey:@“data”]；
NSLog（@“ggg%@，[self.friendsDictionary objectForKey:@“data]”）；
对于（int i=0；i<[[self.friendsDictionary objectForKey:@“data”]计数]；i++）{
[array addObject:[[[self.friendsDictionary objectForKey:@“data”]objectAtIndex:i]objectForKey:@“name”]；
}
NSLog（@“数组%@”，数组）；
if（self.searchDisplayController.searchBar.text.length>0）
{
NSString*strSearchText=self.searchDisplayController.searchBar.text；
NSMutableArray*组=[[NSMutableArray alloc]init]；
对于（int i=0；i 0）
{
searchData=[[NSMutableArray alloc]init]；
[searchData addObjectsFromArray:group]；
NSLog（@“Sear%@”，searchData）；
}
} 
返回YES；
}

那么

nameData

是可变数组的可变数组吗？你就是这样处理的。还有，当组与快速枚举一起使用时，为什么要分配组？实际上组是数组类型。我仍然在获取crashSo

nameData

是数组吗？是或不是，好的，酷。现在请发布堆栈跟踪。如果您刚刚分配了

group

，则

for（）

语句无效，因为

group

将为空。仍在获取错误。“-[\u NSCFString count]：未识别的选择器发送到实例0x1bc3d0”