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Objective c 如何将目标c转换为swift_Objective C_Swift - Fatal编程技术网

Objective c 如何将目标c转换为swift

Objective c 如何将目标c转换为swift,objective-c,swift,Objective C,Swift,我有一个零件代码目标c代码,我想转换成swift: NSString *rawStr = [[tokenField textField] text]; for (int i = 0; i < [rawStr length]; i++) { if (![charSet characterIsMember:[rawStr characterAtIndex:i]]) { [recipi

我有一个零件代码目标c代码,我想转换成swift:

NSString *rawStr = [[tokenField textField] text];
        for (int i = 0; i < [rawStr length]; i++)
        {
            if (![charSet characterIsMember:[rawStr characterAtIndex:i]])
            {
                [recipient appendFormat:@"%@",[NSString stringWithFormat:@"%c", [rawStr characterAtIndex:i]]];
            }
        }
        if ([rawStr length])
        {
            [tokenField addTokenWithTitle:rawStr representedObject:recipient];
        }
NSString*rawStr=[[tokenField textField]text];
对于(int i=0;i<[rawStr长度];i++)
{
if(![charSet characteristember:[rawStr characterAtIndex:i]]
{
[recipient appendFormat:@“%@”,[NSString stringWithFormat:@”%c“,[rawStr characterAtIndex:i]];
}
}
如果([rawStr长度])
{
[tokenField addTokenWithTitle:rawStr representedObject:recipient];
}

请指导我。

如果您不介意使用
NSString
端口是直接的:

    let rawStr:NSString = tokenField.textField.text
    for i in 0..<rawStr.length {
        let currentChar = rawStr.characterAtIndex(i)
        if !charSet.characterIsMember(currentChar) {
            recipient.appendFormat("%@", NSString(format:"%c", currentChar))
        }
    }
    if rawStr.length > 0 {
        tokenField.addTokenWithTitle(rawStr, representedObject:recipient)
    }
让rawStr:NSString=tokenField.textField.text
因为我在0。。0 {
tokenField.addTokenWithTitle(rawStr,representedObject:recipient)
}

否则,
字符串
类没有长度方法。您必须使用
s.startIndex.advancedBy
语法。

看起来您试图保留不在字符集中的字符

func strRemoveCharsNotInSet(str: String) -> String {
    let charSet = NSCharacterSet(charactersInString: ".@")

    let temp = str.componentsSeparatedByCharactersInSet(charSet)
    let backToString = temp.joinWithSeparator("")

    return backToString
}

print(strRemoveChars("Hello@There.Friend"))

outputs:
    HelloThereFriend

如果你否决了投票,至少要说明原因。