Objective c 使用NSPredicate筛选NSNumber的NSArray和NSArray的对象NSArray

我正在尝试对该对象的数组进行文件归档：

MyObject.h

@interface MyObject : NSObject

@property (assign) int id_object;
@property (nonatomic, strong) NSString *name;

@end

例如，在我的第一个数组中，我有一些MyObject：

MyObject *ob1 = [[MyObject alloc] init];
[ob1 setId_Object:1;
[ob1 setName:@"Carl"];

MyObject *ob2 = [[MyObject alloc] init];
[ob2 setId_Object:2;
[ob2 setName:@"Carl"];

MyObject *ob3 = [[MyObject alloc] init];
[ob3 setId_Object:3;
[ob3 setName:@"Carl"];

NSArray *firstArray = [[NSArray alloc] initWithObjects:ob1,ob2,ob3,nil];

然后我想用NSPredicate和NSNumber数组筛选此数组，如下所示：

NSArray *secondArray = [NSArray arrayWithObjects:[NSNumber numberWithInt:1],[NSNumber numberWithInt:2],nil];

我试过这个：

 NSArray *filteredObject = [firstArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"id_object IN %@",secondArray]];

但是filteredObject是空的，我怎么办？

一旦检查这个

 NSArray *filteredObject = [questionSections filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"self.Carl contains %@ OR self.Carl contains %@ ",@"1",@"2"]];

例：-

O/p:--

试着替换

@property (nonatomic, copy) NSNumber* id_object;
@property (nonatomic, copy) NSString *name;

而不是

@property (assign) int id_object;
@property (nonatomic, strong) NSString *name;

---

似乎你的测试用例是错误的。我不认为你的setId_对象做了你认为它做的事，当用一个NSNumber调用它时

[ob1 setId_object:[NSNumber numberWithInt:1]];
NSLog(@"%d", ob1.id_object);

> 391

[ob1 setId_object:1];
NSLog(@"%d", ob1.id_object);

> 1

替换初始化会使测试用例正常运行

编辑：我的测试用例，剪切粘贴

MyObject *ob1 = [[MyObject alloc] init]; ob1.id_object = 1; [ob1 setName:@"Carl"];
MyObject *ob2 = [[MyObject alloc] init]; ob2.id_object = 2; [ob2 setName:@"Carl"];
MyObject *ob3 = [[MyObject alloc] init]; ob3.id_object = 3; [ob3 setName:@"Carl"];

NSArray *firstArray = [[NSArray alloc] initWithObjects:ob1,ob2,ob3,nil];
NSArray *secondArray = [NSArray arrayWithObjects:[NSNumber numberWithInt:1],[NSNumber numberWithInt:2],nil];

NSArray *filteredObject = [firstArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"id_object IN %@",secondArray]];

NSLog(@"%@", filteredObject);

>>> <MyObject: 0x100110350> {1,"Carl"}
>>> <MyObject: 0x1001104b0> {2,"Carl"}

MyObject*ob1=[[MyObject alloc]init]；ob1.id_object=1；[ob1集合名：@“卡尔”]；
MyObject*ob2=[[MyObject alloc]init]；ob2.id_object=2；[ob2集合名：@“Carl”]；
MyObject*ob3=[[MyObject alloc]init]；ob3.id_object=3；[ob3集合名：@“Carl”]；
NSArray*firstArray=[[NSArray alloc]initWithObjects:ob1、ob2、ob3、nil]；
NSArray*secondArray=[NSArray arrayWithObjects:[NSNumber numberWithInt:1]，[NSNumber numberWithInt:2]，nil]；
NSArray*filteredObject=[firstArray FilteredArray UsingPredicate:[NSPredicate predicateWithFormat:@“id\u对象在%@”，secondArray]]；
NSLog（@“%@”，过滤器对象）；
>>>{1，“卡尔”}
>>>{2，“卡尔”}

向我们显示firstArray数组数据。我已编辑完毕。您需要传递字符串而不是数组。字符串是什么？你能回答这个问题吗？这只是一个例子，我用另一种方式填充firstArray，但我很确定数组包含正确的值，我的问题只是关于如何过滤该数组…你能回答这个问题吗？@Piero进行小的修复可以让你的代码为我以正确的结果运行。我可以添加完整的测试用例。@Piero用我的测试用例更新了。

[ob1 setId_object:[NSNumber numberWithInt:1]];
NSLog(@"%d", ob1.id_object);

> 391

[ob1 setId_object:1];
NSLog(@"%d", ob1.id_object);

> 1

MyObject *ob1 = [[MyObject alloc] init]; ob1.id_object = 1; [ob1 setName:@"Carl"];
MyObject *ob2 = [[MyObject alloc] init]; ob2.id_object = 2; [ob2 setName:@"Carl"];
MyObject *ob3 = [[MyObject alloc] init]; ob3.id_object = 3; [ob3 setName:@"Carl"];

NSArray *firstArray = [[NSArray alloc] initWithObjects:ob1,ob2,ob3,nil];
NSArray *secondArray = [NSArray arrayWithObjects:[NSNumber numberWithInt:1],[NSNumber numberWithInt:2],nil];

NSArray *filteredObject = [firstArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"id_object IN %@",secondArray]];

NSLog(@"%@", filteredObject);

>>> <MyObject: 0x100110350> {1,"Carl"}
>>> <MyObject: 0x1001104b0> {2,"Carl"}