Oracle查询以查找表中不存在的记录？

这可能是一个简单的查询，但我似乎无法编写它

如何在表中查找表中没有以下值的所有记录

因此，对于下面的帐户，我需要在这个表中插入 价值观

Account = Test003
Role    = Owner
Grp     = AO1

因为此表中没有任何包含Role或Grp=的列

--------------------------------------------------
| ACCOUNT          |   ROLE  |    GRP   |
--------------------------------------------------

| Test003          | Overlay |    WAD    |

---

要使合并生效，请使用双表为正在搜索的值生成一行

merge into your_table yt
using ( select 'Test003' as acct
                , 'Owner' as role
                , 'AO1' as grp
        from dual ) q
  on (yt.account = q.acct
  and yt.role = q.role
  and yt.grp = q.grp)
when not matched then
  insert (account, role, grp)
  values (q.acct, q.role, q.grp)

---

如果要合并多个记录，可以在USING中使用UNION ALL在DUAL上创建一组多个查询

我就是这样理解这个问题的：

SQL> create table test
  2    (account    varchar2(10),
  3     role       varchar2(10),
  4     grp        varchar2(10));

Table created.

SQL> -- insert sample data
SQL> insert into test
  2    (select 'test001', 'actor'   , 'a01' from dual union  --> contains GRP
  3     select 'test002', 'director', 'd02' from dual union
  4     select 'test003', 'owner'   , 'a01' from dual union  --> contains ROLE and GRP
  5     select 'test004', 'overlay' , 'wad' from dual
  6    );

4 rows created.

SQL>

上面的示例数据意味着我应该为test002和test004帐户插入owner和a01，因为它们既没有role=owner，也没有grp=a01

SQL> insert into test (account, role, grp)
  2    (select x.account, 'owner', 'a01'
  3     from (select account
  4           from test
  5           where role <> 'owner'
  6             and grp <> 'a01'
  7          ) x
  8    );

2 rows created.

SQL> select * from test
  2  order by account, role, grp;

ACCOUNT    ROLE       GRP
---------- ---------- ----------
test001    actor      a01
test002    director   d02
test002    owner      a01
test003    owner      a01
test004    overlay    wad
test004    owner      a01

6 rows selected.

SQL>

---

你的问题不是很清楚。您是否尝试：查询所有不具有Account=Test003、Role=Owner和Grp=AO1值的行？或者您正在尝试将这些值插入到有问题的表中？