Php OOP返回一些不可接受的数组
好的,我尝试在类文件中返回一个数组,并像array['variable']那样回显数组;但出于某种原因,它表示[]括号内的变量未定义,但当我var_转储数组时,它会正常显示所有数组内容。这是我的密码: Login.class.phpPhp OOP返回一些不可接受的数组,php,arrays,oop,pdo,Php,Arrays,Oop,Pdo,好的,我尝试在类文件中返回一个数组,并像array['variable']那样回显数组;但出于某种原因,它表示[]括号内的变量未定义,但当我var_转储数组时,它会正常显示所有数组内容。这是我的密码: Login.class.php <?php class login { public $database; public $username; public $password; function __constr
<?php
class login {
public $database;
public $username;
public $password;
function __construct($database, $username, $password) {
$this->database = $database;
$this->username = $username;
$this->password = $password;
}
public function encrypt() {
return md5(md5($this->password));
}
public function doLogin() {
$IsVerified = $this->database->getRows("SELECT * FROM `users` WHERE `username` = ? AND `password` = ?", array($this->username, $this->encrypt()));
return $IsVerified;
}
}
config.php
<?php
class config
{
public $isConnected;
protected $datab;
public $username;
public $password;
public $dbname;
public $host;
public function __construct($options=array()){
$this->username = "root";
$this->password = "";
$this->dbname = "";
$this->host = "localhost";
$this->isConnected = true;
try {
$this->datab = new PDO("mysql:host={$this->host};dbname={$this->dbname};charset=utf8", $this->username, $this->password, $options);
$this->datab->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$this->datab->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
}
catch(PDOException $e) {
$this->isConnected = false;
throw new Exception($e->getMessage());
}
}
public function Disconnect(){
$this->datab = null;
$this->isConnected = false;
}
public function getRow($query, $params=array()){
try{
$stmt = $this->datab->prepare($query);
$stmt->execute($params);
return $stmt->fetch();
}catch(PDOException $e){
throw new Exception($e->getMessage());
}
}
public function getRows($query, $params=array()){
try{
$stmt = $this->datab->prepare($query);
$stmt->execute($params);
return $stmt->fetchAll();
}catch(PDOException $e){
throw new Exception($e->getMessage());
}
}
public function getRowCount($query, $params=array()){
try{
$stmt = $this->datab->prepare($query);
$stmt->execute($params);
return $stmt->rowCount();
}catch(PDOException $e){
throw new Exception($e->getMessage());
}
}
public function insertRow($query, $params){
try{
$stmt = $this->datab->prepare($query);
$stmt->execute($params);
}catch(PDOException $e){
throw new Exception($e->getMessage());
}
}
public function updateRow($query, $params){
return $this->insertRow($query, $params);
}
public function deleteRow($query, $params){
return $this->insertRow($query, $params);
}
}
?>
当我尝试回显$userdata['firstname']时;上面说
“注意:第13行C:\xampp\htdocs\site\login.php中未定义的索引:firstname”
但当I var_dump时,它会显示所有阵列内容。
非常感谢您的帮助
这是请求的var_转储
array(1) {
[0]=> array(10) {
["id"]=> string(1) "0"
["username"]=> string(7) "patrick"
["password"]=> string(32) "432g1hjkgj2hgjhg34342"
["groupid"]=> string(1) "1"
["email"]=> string(15) "email@gmail.com"
["verified"]=> string(1) "0"
["birthday"]=> string(0) ""
["firstname"]=> string(4) "john"
["lastname"]=> string(9) "cena"
["regdate"]=> string(0) ""
}
}
var_dump()
会使这更容易,但是在doLogin()
方法中,您正在调用getRows()
方法,该方法反过来调用PDO对象
因此,您可能需要:
$UserData[0]['firstname']
Edit:刚刚被
var\u dump()
确认,那么,它应该是$UserData[0]['firstname']。请参见它可能是一个对象,而不是数组。尝试访问属性,如$userdata->firstname已经尝试过了,说它不是一个“试图获取非对象属性”的对象。你能添加var\u dump()
?下次你自己要找到问题,需要做的是在回显之前导出($userdata)。这样,您就可以清楚地识别您试图访问的内容。如果它是空的,请尝试返回并调试数据丢失的原因所有这些工作都可以使用MD5(tsk tsk)。使用或PHP5.5的函数。我喜欢人们以秒为单位互相殴打:-)@ManuelArwedSchmidt同意。然而,我要说的是,jeroen在var_dump()之前就知道问题所在。
array(1) {
[0]=> array(10) {
["id"]=> string(1) "0"
["username"]=> string(7) "patrick"
["password"]=> string(32) "432g1hjkgj2hgjhg34342"
["groupid"]=> string(1) "1"
["email"]=> string(15) "email@gmail.com"
["verified"]=> string(1) "0"
["birthday"]=> string(0) ""
["firstname"]=> string(4) "john"
["lastname"]=> string(9) "cena"
["regdate"]=> string(0) ""
}
}
$UserData[0]['firstname']