将字符串转换为可执行表达式PHP?
我正在开发ExpressionBuilder,用户可以在其中添加许多规则 我试图把规则转换成一个表达式,但是PHP总是考虑字符串,并且总是返回<代码>真< /代码> .< 有没有办法使该表达式可执行将字符串转换为可执行表达式PHP?,php,string,laravel,expression,Php,String,Laravel,Expression,我正在开发ExpressionBuilder,用户可以在其中添加许多规则 我试图把规则转换成一个表达式,但是PHP总是考虑字符串,并且总是返回真< /代码> .< 有没有办法使该表达式可执行 public function translate($record = null){ $rule = $this->rule; $conditions = []; if( count($rule->rules) ){ $la
public function translate($record = null){
$rule = $this->rule;
$conditions = [];
if( count($rule->rules) ){
$last_key = key( array_slice( $rule->rules, -1, 1, TRUE ) );
foreach ($rule->rules as $key => $value) {
$conditions[] = '"'.$record->{$value->field} .'" ' . $this->operator($value->operator) .' "'. $value->value.'"';
}
}
$condition = implode(' '.$rule->condition.' ', $conditions);
return $condition;// result : "Full Packaged Product" == "Full Packaged Product" AND "No" != "Y"
}
// using here
foreach( $records as $ind => $record ){
foreach( $rules as $rule){
// $condition = $rule->translate(collect($record));
$condition = $rule->translate($record);
if($condition){
dump('Pass', $condition);
}else{
dump('Fail', $condition);
}
}
}
我还尝试使用eval()
PHP函数,但没有成功
谢谢,
Kaleem如果您确定代码是安全的,您可以使用eval()
用法:
eval('$res = "yes" == "no" ;');
var_dump($res); // bool(false)