Php 从集合对象获取值
这对你来说可能很愚蠢,但对于像我这样的学习者来说,这有点像噩梦: 我有:Php 从集合对象获取值,php,arrays,object,collections,Php,Arrays,Object,Collections,这对你来说可能很愚蠢,但对于像我这样的学习者来说,这有点像噩梦: 我有: $memberObject->picturesCollection 这在控制台中显示: : object(Collection) = elements: array = 0: object(Pic) = fileName: string = %2Ffolder%2F2%2F9A246297-48CB-4A7A-92FB-B5C18D44E756.JPG bPicExists
$memberObject->picturesCollection
这在控制台中显示:
: object(Collection) =
elements: array =
0: object(Pic) =
fileName: string = %2Ffolder%2F2%2F9A246297-48CB-4A7A-92FB-B5C18D44E756.JPG
bPicExists: bool = TRUE
counter: long = 1
pointer: long = 1
我需要得到文件名
我该怎么做
非常感谢 诸如此类:
$memberObject->picturesCollection->elements[0]->filename
它取决于属性的可见性。如果它们是私有的,你需要使用getter。你能试试var\u dump$memberObject;然后把结果贴在这里?