Php 从两个列相同的表中选择数据，查询不完全正确？

我试图从两个表中提取数据，其中

prop\u slug

和

prop\u gallery\u id

匹配。我已经写了下面的语句，只是我似乎无法让它工作，而且我的语法不断出错-有人能看到我的查询中是否有明显的错误吗

$listings = $db->query('
SELECT * 
  FROM listing_details 
  JOIN prop_gallery 
    ON prop_gallery.prop_gallery_id = listing_details.prop_slug 
 WHERE (listing_details.prop_slug LIKE \'prop_gallery_id\' OR prop_gallery.prop_gallery_id LIKE \'prop_slug\') 
   AND 
 WHERE listing_details.prop_mandate = 1 
 LIMIT 3')->fetchAll();

---

您不需要第二个

WHERE

$listings = $db->query('
SELECT * 
  FROM listing_details 
  JOIN prop_gallery 
    ON prop_gallery.prop_gallery_id = listing_details.prop_slug 
 WHERE (listing_details.prop_slug LIKE \'prop_gallery_id\' OR prop_gallery.prop_gallery_id LIKE \'prop_slug\') 
   AND listing_details.prop_mandate = 1 
 LIMIT 3')->fetchAll();

---

您能找到任何带有多个WHERE子句的查询示例吗？另外，请注意，没有ORDER BY的限制是相当没有意义的。要获得进一步的帮助，请参阅我认为您添加了两个where子句，因为您得到了语法错误。尝试在和之后删除where子句。