Php 徽章原因错误
我试图在我们的系统上展示徽章,徽章是对用户的奖励/成就。他们在个人资料上显示,有效的是图像/徽章显示,但徽章原因不起作用 我试着这样做Php 徽章原因错误,php,mysql,html,Php,Mysql,Html,我试图在我们的系统上展示徽章,徽章是对用户的奖励/成就。他们在个人资料上显示,有效的是图像/徽章显示,但徽章原因不起作用 我试着这样做 <? $badgesql = mysql_query("select * from usr_badge where user = '$user'"); $user2 = mysql_query("select * from usr_users where username = '$user'"); $usr2 = mysql_fet
<?
$badgesql = mysql_query("select * from usr_badge where user = '$user'");
$user2 = mysql_query("select * from usr_users where username = '$user'");
$usr2 = mysql_fetch_array($user2);
$vipsql = mysql_query("select * from usr_vip where userid = '$usr2[id]'");
$vipcheck = mysql_num_rows($vipsql);
$badgecheck = mysql_num_rows($badgesql);
$checkit = $badgecheck + $vipcheck;
if($checkit==0)
echo("This user does not have any badges");
else
if($badgecheck!=0)
{
while($badge = mysql_fetch_array($badgesql))
{
echo('<a onclick="TINY.box.show({html:'Reason: '.$badge[reason].',animate:false,close:false,mask:false,boxid:'success',autohide:2,top:-14,left:-17})"><img src="'.$badge[badge].'" </a>');
}
}
//Display VIP Badges
if($vipcheck!=0)
{
$vipbadge = mysql_fetch_array($vipsql);
$vip1 = mysql_query("select * from usr_vipdb where id = '$vipbadge[vipid]'");
$vip2 = mysql_fetch_array($vip1);
echo('<img src="'.$vip2[url].'" alt="This user is a VIP!" />');
}
?>
以echo
开头的那条长线可能是错误的——此处突出显示的语法与之不符,表明您可能与引号或类似内容不匹配。(把它分开。把每一小段放在自己的线上。这样你就不会错过错误了。)
以下是您当前的代码,我相信解释器会解析它:
echo('<a onclick="TINY.box.show({html:'
Reason: '.$badge[reason].'
,animate:false,close:false,mask:false,boxid:
'success'
,autohide:2,top:-14,left:-17})
"><img src="
'.$badge[badge].'
" </a>');
echo('and.试试这个(我想是固定的开/关引号)
我也猜你的开放式和封闭式引用不一致。简单地从代码块中突出显示的语法判断,我还发现了一个开放式img
标记,我刚刚在回答中更正了它。我刚刚恢复了对这篇文章的编辑-一般来说,一旦有人问了问题,它应该只进行调整,以便得到相应的答案这仍然有意义。如果你有一个完全不同的问题要问,打开一个新问题。至少这里的突出显示是固定的。:@sarnold我有一段时间没有做PHP了。。。这是个不好的地方吗?或者不是真的?我试过了,错误消失了,我可以查看徽章,但当我点击图像弹出原因时,它就不存在了。谢谢你的帮助,凯尔。:)@凯尔,我认为这对一个医生来说有点过分了,但把它分成三行或四行不会有任何伤害@Hillajannar:这不是一个修复。它只是想指出你的字符串极其复杂。凯尔在他的回答中找到了最终的解决方案。
<?
$badgesql = mysql_query("select * from usr_badge where user = '$user'");
$user2 = mysql_query("select * from usr_users where username = '$user'");
$usr2 = mysql_fetch_array($user2);
$vipsql = mysql_query("select * from usr_vip where userid = '$usr2[id]'");
$vipcheck = mysql_num_rows($vipsql);
$badgecheck = mysql_num_rows($badgesql);
$checkit = $badgecheck + $vipcheck;
if($checkit==0) {
echo("This user does not have any badges");
} else {
if($badgecheck!=0)
{
while($badge = mysql_fetch_array($badgesql))
{
echo('<a onclick="TINY.box.show({html: "Reason: '.$badge[reason].'",animate:false,close:false,mask:false,boxid:"success",autohide:2,top:-14,left:-17})"><img src="'.$badge[badge].'" /></a>');
}
}
//Display VIP Badges
if($vipcheck!=0)
{
$vipbadge = mysql_fetch_array($vipsql);
$vip1 = mysql_query("select * from usr_vipdb where id = '$vipbadge[vipid]'");
$vip2 = mysql_fetch_array($vip1);
echo('<img src="'.$vip2[url].'" alt="This user is a VIP!" />');
}
}
?>