Php 按键拆分和分组数组

好的，我已经做了一些搜索，但还没有找到答案，所以我要尝试一下

我有一个JSON文件，可以输出以下信息：

[
    {
        "Contact name(s)": "Person 1, Person 2",
        "Contact title(s)": "Head Comacho, Other Guy",
        "Contact email(s)": "email1@email.net, email@email.com",
        "Contact phone": "123-456-7890, 789-456-1230",
    },
    {   
        "Contact name(s)": "Some Dude",
        "Contact title(s)": "Cool Title",
        "Contact email(s)": "things@email.com",
        "Contact phone": "555-555-5555",
    },
        "Contact name(s)": "",
        "Contact title(s)": "",
        "Contact email(s)": "",
        "Contact phone": "",
    }
]

不幸的是，这就是数据的命名方式。从我手中。无论如何，我必须得到它，这样这些有多个联系人的人将分组到他们自己的阵列中。以下是它需要的外观：

Array
(
    [0] => Array
        (
            [contact_name] => Person 1
            [contact_title] => Head Comacho
            [contact_email] => email1@email.net
            [contact_phone] => 123-456-7890
        )

    [1] => Array
        (
            [contact_name] => Person 2
            [contact_title] => Other Title
            [contact_email] => email@email.com
            [contact_phone] => 789-456-1230
        )
)
Array
(
    [0] => Array
        (
            [contact_name] => Some Dude
            [contact_title] => Cool Title
            [contact_email] => things@email.com
            [contact_phone] => 555-555-5555
        )
)
Array
(
    [0] => Array
        (
            [contact_name] => 
            [contact_title] => 
            [contact_email] => 
            [contact_phone] => 
        )
)

我能够将数据转换为它们自己的数组，如下所示：

Array
(
    [contact_name] => Array
        (
            [0] => Person 1
            [1] => Person 2
        )

    [contact_title] => Array
        (
            [0] => Head Comacho
            [1] => Other Guy
        )

    [contact_email] => Array
        (
            [0] => email1@email.net
            [1] => email@email.com
        )

    [contact_phone] => Array
        (
            [0] => 123-456-7890
            [1] => 789-456-1230
        )

)

Array
(
 .....etc
)

我如何才能像第一个例子那样得到它

---

道歉如果之前有人回答过，我不知道该如何回答我的问题。非常感谢您提供的所有帮助。

如果您可以确保多人的json对象始终包含相同数量的元素，那么您可以这样做：

<?php

$json = '[
    {"Contact name(s)": "Person 1, Person 2", "Contact title(s)": "Head Comacho, Other Guy", "Contact email(s)": "email1@email.net, email@email.com", "Contact phone": "123-456-7890, 789-456-1230"},
    {"Contact name(s)": "Some Dude", "Contact title(s)": "Cool Title", "Contact email(s)": "things@email.com", "Contact phone": "555-555-5555"},
    {"Contact name(s)": "", "Contact title(s)": "", "Contact email(s)": "", "Contact phone": ""}
]';

$jsonA = json_decode($json, true);

$result = [];
$maxLen = 0;
foreach ($jsonA as &$obj) {
    foreach ($obj as $k => $v) {
        if (!isset($result[$k])) $result[$k] = [];
        foreach (explode(',', $v) as $av) $result[$k][] = trim($av);
        $maxLen = max($maxLen, count($result[$k]));
    }
}

$objects = [];
for ($i=0; $i<$maxLen; $i++) {
    $object = [];
    foreach (array_keys($result) as $k) $object[$k] = isset($result[$k][$i]) ? $result[$k][$i] : '';
    $objects[] = $object;
}

echo '<pre>';
print_r($objects);

---

我想这个脚本可以满足你的要求。我已经创建了一个函数

split_contacts

，它获取解码数组中的每个条目，并将值（例如

“Person 1，Person 2”

=>[“Person 1”，“Person 2”]）拆分成由对象键索引的数组，对象键由

preg_replace

按您想要的形式（例如

“Contact name（s）”=>“contact_name”

）。请注意，可以使用

str_replace

而不是

preg_replace

，但我希望在键值格式方面保持代码的灵活性

Array
(
    [0] => Array
        (
            [0] => Array
                (
                    [contact_name] => Person 1
                    [contact_title] => Head Comacho
                    [contact_email] => email1@email.net
                    [contact_phone] => 123-456-7890
                )    
            [1] => Array
                (
                    [contact_name] =>  Person 2
                    [contact_title] =>  Other Guy
                    [contact_email] =>  email@email.com
                    [contact_phone] =>  789-456-1230
                )    
        )    
    [1] => Array
        (
            [0] => Array
                (
                    [contact_name] => Some Dude
                    [contact_title] => Cool Title
                    [contact_email] => things@email.com
                    [contact_phone] => 555-555-5555
                )    
        )    
    [2] => Array
        (
            [0] => Array
                (
                    [contact_name] => 
                    [contact_title] => 
                    [contact_email] => 
                    [contact_phone] => 
                )    
        )    
)

输出：

$arr = '[
    {
        "Contact name(s)": "Person 1, Person 2",
        "Contact title(s)": "Head Comacho, Other Guy",
        "Contact email(s)": "email1@email.net, email@email.com",
        "Contact phone": "123-456-7890, 789-456-1230"
    },
    {   
        "Contact name(s)": "Some Dude",
        "Contact title(s)": "Cool Title",
        "Contact email(s)": "things@email.com",
        "Contact phone": "555-555-5555"
    },
    {
        "Contact name(s)": "",
        "Contact title(s)": "",
        "Contact email(s)": "",
        "Contact phone": ""
    }
]';

$arr = json_decode($arr, true);

foreach ($arr as $row) {

    list($m_name, $m_title, $m_email, $m_phone) =
    [explode(',', $row["Contact name(s)"]),explode(',', $row["Contact title(s)"]),
     explode(',', $row["Contact email(s)"]),explode(',', $row["Contact phone"])];

    foreach (array_keys($m_name) as $per)
        $result[] = ['name' => $m_name[$per],'title' => $m_title[$per],
                     'email' => $m_email[$per],'phone' => $m_phone[$per]];
}

var_dump($result);

---

我找到了这个解决方案：

$json = '[
    {"Contact name(s)": "Person 1, Person 2", "Contact title(s)": "Head Comacho, Other Guy", "Contact email(s)": "email1@email.net, email@email.com", "Contact phone": "123-456-7890, 789-456-1230"},
    {"Contact name(s)": "Some Dude", "Contact title(s)": "Cool Title", "Contact email(s)": "things@email.com", "Contact phone": "555-555-5555"},
    {"Contact name(s)": "", "Contact title(s)": "", "Contact email(s)": "", "Contact phone": ""}
]';
$array = json_decode($json, true);

$trans = [
    "Contact name(s)" => "contact_name",
    "Contact title(s)" => "contact_title",
    "Contact email(s)" => "contact_email",
    "Contact phone" => "contact_phone"    
];

foreach ($array as $set) {
    $temp = [];
    foreach ($set as $key => $data) {
        foreach (explode(', ', $data) as $index => $value) {
            $temp[$index][$trans[$key]] = $value;     
        }
    }
    $result[] = $temp;
}
var_export($result);

---

如果这是我的项目，这就是我要做的，为什么

您需要将每个数据子集彼此分开，因此在外循环迭代之间使用

$temp

作为临时存储。必须在每个新的

$set

开始时重置临时数组，并且必须将临时数组数据传输到

$result

数组以维护原始的集合索引

explode（）

最好使用“逗号空间”作为分隔符参数——这样就不必调用任何附加函数来清除延迟的空间

因为您的新旧密钥是已知的且是静态的，所以硬编码关联的“转换”数组将节省大量迭代函数调用，并在很大程度上减少代码膨胀。我还将指出，这使您能够更简单地控制密钥准备，未来的开发人员将能够很快理解您的代码在做什么

代码：（）

输出：

$arr = '[
    {
        "Contact name(s)": "Person 1, Person 2",
        "Contact title(s)": "Head Comacho, Other Guy",
        "Contact email(s)": "email1@email.net, email@email.com",
        "Contact phone": "123-456-7890, 789-456-1230"
    },
    {   
        "Contact name(s)": "Some Dude",
        "Contact title(s)": "Cool Title",
        "Contact email(s)": "things@email.com",
        "Contact phone": "555-555-5555"
    },
    {
        "Contact name(s)": "",
        "Contact title(s)": "",
        "Contact email(s)": "",
        "Contact phone": ""
    }
]';

$arr = json_decode($arr, true);

foreach ($arr as $row) {

    list($m_name, $m_title, $m_email, $m_phone) =
    [explode(',', $row["Contact name(s)"]),explode(',', $row["Contact title(s)"]),
     explode(',', $row["Contact email(s)"]),explode(',', $row["Contact phone"])];

    foreach (array_keys($m_name) as $per)
        $result[] = ['name' => $m_name[$per],'title' => $m_title[$per],
                     'email' => $m_email[$per],'phone' => $m_phone[$per]];
}

var_dump($result);

---

您会发现这个解决方案不仅简洁、准确、易读；而且非常有效，因为整个过程中只有一个迭代函数调用（

explode（）

）。

您是否缺少一些字段？正如现在一样，JSON是无效的（最后一个字段上多了逗号，最后一个对象上缺少左括号）.由于所提供的示例数据不需要regex，我宁愿看到更轻的调用：

str_replace（）

@mickmackusa我试图保持代码的灵活性…我不知道OPs数据的其他部分是什么样的请对此代码的唯一答案添加一些解释，以提高其整体教育价值。@mickmackusa您的愿望…哦，等等，不，不是：-）。但这是一个公平的评论，肯定这个答案可以使用一些，我已经这样做了。

$json = '[
    {"Contact name(s)": "Person 1, Person 2", "Contact title(s)": "Head Comacho, Other Guy", "Contact email(s)": "email1@email.net, email@email.com", "Contact phone": "123-456-7890, 789-456-1230"},
    {"Contact name(s)": "Some Dude", "Contact title(s)": "Cool Title", "Contact email(s)": "things@email.com", "Contact phone": "555-555-5555"},
    {"Contact name(s)": "", "Contact title(s)": "", "Contact email(s)": "", "Contact phone": ""}
]';
$array = json_decode($json, true);

$trans = [
    "Contact name(s)" => "contact_name",
    "Contact title(s)" => "contact_title",
    "Contact email(s)" => "contact_email",
    "Contact phone" => "contact_phone"    
];

foreach ($array as $set) {
    $temp = [];
    foreach ($set as $key => $data) {
        foreach (explode(', ', $data) as $index => $value) {
            $temp[$index][$trans[$key]] = $value;     
        }
    }
    $result[] = $temp;
}
var_export($result);

array (
  0 => 
  array (
    0 => 
    array (
      'contact_name' => 'Person 1',
      'contact_title' => 'Head Comacho',
      'contact_email' => 'email1@email.net',
      'contact_phone' => '123-456-7890',
    ),
    1 => 
    array (
      'contact_name' => 'Person 2',
      'contact_title' => 'Other Guy',
      'contact_email' => 'email@email.com',
      'contact_phone' => '789-456-1230',
    ),
  ),
  1 => 
  array (
    0 => 
    array (
      'contact_name' => 'Some Dude',
      'contact_title' => 'Cool Title',
      'contact_email' => 'things@email.com',
      'contact_phone' => '555-555-5555',
    ),
  ),
  2 => 
  array (
    0 => 
    array (
      'contact_name' => '',
      'contact_title' => '',
      'contact_email' => '',
      'contact_phone' => '',
    ),
  ),
)