Php 与目标的链接="_“空白”;在safari view controller中查看jquery mobile时需要单击两次
我有一个jquery移动web应用程序,其链接如下所示:Php 与目标的链接="_“空白”;在safari view controller中查看jquery mobile时需要单击两次,php,jquery-mobile,user-agent,sfsafariviewcontroller,Php,Jquery Mobile,User Agent,Sfsafariviewcontroller,我有一个jquery移动web应用程序,其链接如下所示: <a href="EXTERNAL_URL" class="ui-btn" rel="external" target="_blank">LINK TEXT</a> if (((strstr($_SERVER['HTTP_USER_AGENT'],'iPhone')) || (strstr($_SERVER['HTTP_USER_AGENT'],'iPad'))) && (strstr($_SER
<a href="EXTERNAL_URL" class="ui-btn" rel="external" target="_blank">LINK TEXT</a>
if (((strstr($_SERVER['HTTP_USER_AGENT'],'iPhone')) ||
(strstr($_SERVER['HTTP_USER_AGENT'],'iPad')))
&&
(strstr($_SERVER['HTTP_USER_AGENT'],'Safari'))){
//
}else{
$blank='target="blank"';
}
然后将$blank放入链接:
<a href="EXTERNAL_URL" class="ui-btn" rel="external" <?=$blank?>>LINK TEXT</a>
有没有更聪明的方法