Php Symfony-查询和

我正在写一个查询，它将返回该用户的总花费金额。支出总额=所有交易金额之和，其中类型=支出。我已将基中的类型字段设置为“花费”

它回来了

无效参数：查询中未定义令牌类型

我的密码

public function getTotal(User $user, $type)
{
    $query = $this->getSpendingRepository()
        ->createQueryBuilder('p')
        ->select("sum(p.amount) as total_amount")
        ->where('p.type = :spend')
        ->andWhere('p.user = :user')
        ->setParameters(['user' => $user,
                         'type' => $type])
        ->getQuery()
        ->getOneOrNullResult();

    return $query;
}

这就是sql，它正在工作，所以我不知道我做错了什么

select user_id, sum(amount) as amount
from transaction
where type = 'spend'
group by user_id

替换

->where('p.type = :spend')

与

我修好了

 public function getTotalSpent(User $user, $type = 'spend')
{
    $query = $this->getTransactionRepository()
        ->createQueryBuilder('p')
        ->select("sum(p.amount) as total_amount")
        ->where('p.type = :type')
        ->andWhere('p.user = :user')
        ->setParameters(['user' => $user,
                         'type' => $type])
        ->getQuery()
        ->getOneOrNullResult();

    return $query;
}

---

加油：

：expense

不是

类型

我想在那里定义字段“type”的值。。还有别的办法吗？你真的确定吗？你试过了吗<代码>：expense是查询中变量的名称。错误清楚地表明，在查询中找不到变量

type

。因为您将其命名错误。Expense是我在db表的“type”字段中输入的值。。其中type='spend'按用户分组在查询中定义了变量“：spend”和“：user”，但通过

setParameters

传递“type”和“user”的值。这个答案实际上应该解决问题。

 public function getTotalSpent(User $user, $type = 'spend')
{
    $query = $this->getTransactionRepository()
        ->createQueryBuilder('p')
        ->select("sum(p.amount) as total_amount")
        ->where('p.type = :type')
        ->andWhere('p.user = :user')
        ->setParameters(['user' => $user,
                         'type' => $type])
        ->getQuery()
        ->getOneOrNullResult();

    return $query;
}