Php 从查询在while循环中创建关联数组
我得到一个例子:Php 从查询在while循环中创建关联数组,php,mysql,sql,arrays,Php,Mysql,Sql,Arrays,我得到一个例子: <?php $shop = array( array( Title => "rose", Price => 1.25, Number => 15 ), array( Title => "daisy", Price => 0.75, Numb
<?php
$shop = array( array( Title => "rose",
Price => 1.25,
Number => 15
),
array( Title => "daisy",
Price => 0.75,
Number => 25,
),
array( Title => "orchid",
Price => 1.15,
Number => 7
)
);
?>
你在找这个吗?这将提供$预订,其结构与您显示的结构类似
$result2 = mysqli_query($con, "SELECT r.id AS id, CONCAT(g.fname,' ',g.lname) AS name,
r.arrival AS arrival, r.departure AS departure
FROM reservations r JOIN guests g ON r.guest = g.id
WHERE r.unit = ".$unit_id."");
$reservations = array(); // makes sure the array exists in case result set is empty
while ($row = mysqli_fetch_assoc($result2))
{
$reservations[] = array (id => $row['id'],
name => $row['name'],
arrival => $row['arrival'],
departure => $row['departure'],
);
}
访问权限如下:
foreach ($reservations as $row){
echo $row["name"]." arrival ". $row["arrival"];
echo "<br />";
}
foreach($row形式的预订){
echo$row[“name”]“arrival”。$row[“arrival”];
回声“
”;
}
您还可以访问:
for ($row = 0; $row<count($reservations); $row++){
echo $reservations[$row]["name"]." arrival ". $reservations[$row]["arrival"];
echo "<br />";
}
for($row=0;$row您在找这个吗?这将为$reservations提供与您显示的结构类似的结构
$result2 = mysqli_query($con, "SELECT r.id AS id, CONCAT(g.fname,' ',g.lname) AS name,
r.arrival AS arrival, r.departure AS departure
FROM reservations r JOIN guests g ON r.guest = g.id
WHERE r.unit = ".$unit_id."");
$reservations = array(); // makes sure the array exists in case result set is empty
while ($row = mysqli_fetch_assoc($result2))
{
$reservations[] = array (id => $row['id'],
name => $row['name'],
arrival => $row['arrival'],
departure => $row['departure'],
);
}
访问权限如下:
foreach ($reservations as $row){
echo $row["name"]." arrival ". $row["arrival"];
echo "<br />";
}
foreach($row形式的预订){
echo$row[“name”]“arrival”。$row[“arrival”];
回声“
”;
}
您还可以访问:
for ($row = 0; $row<count($reservations); $row++){
echo $reservations[$row]["name"]." arrival ". $reservations[$row]["arrival"];
echo "<br />";
}
对于($row=0;$row这个呢:
$result2 = mysqli_query($con, "SELECT r.id AS id, CONCAT(g.fname,' ',g.lname) AS name,
r.arrival AS arrival, r.departure AS departure
FROM reservations r JOIN guests g ON r.guest = g.id
WHERE r.unit = ".$unit_id."");
while($row = mysqli_fetch_assoc($result2) $reservations[] = $row;
本说明:
$reservations[] = $row;
意味着$reservations是一个数组,我们将在下一个键上用$row追加此数组($reservations[next key]=$row)这是怎么回事:
$result2 = mysqli_query($con, "SELECT r.id AS id, CONCAT(g.fname,' ',g.lname) AS name,
r.arrival AS arrival, r.departure AS departure
FROM reservations r JOIN guests g ON r.guest = g.id
WHERE r.unit = ".$unit_id."");
while($row = mysqli_fetch_assoc($result2) $reservations[] = $row;
本说明:
$reservations[] = $row;
意味着$reservations是一个数组,我们将在下一个键上用$row追加这个数组($reservations[next key]=$row)查询将返回x
行数。因此我想对此进行说明。对我来说,这看起来就像每次迭代都会重新创建数组,并且在完成时只包含查询中的最后一行。如果查询返回的行数是多少,它将使用x
元素数创建$reservation。好吗。如何访问一行?例如,在我的第一个示例中,可以这样访问数据:For($row=0;$row<3;$row++){echo$shop[$row][“Title”]。“costs”。“$shop[$row][“Price”]”。您可以得到“$shop[$row][“Number”];echo”
“;}
好的,我稍后会尝试一下,看看是否一切都正常。看起来会。非常感谢。查询将返回x
行数。因此我想对此进行说明。对我来说,这看起来就像每次迭代都会重新创建数组,并且在完成时只包含查询中的最后一行。它将创建$withx
元素数,如果这是查询返回的行数。好的。如何访问行?例如,在我的第一个示例中,可以这样访问数据:For($row=0;$row<3;$row++){echo$shop[$row][“Title”]。“costs”。$shop[$row][“Price”]。“$shop[$row][“number”];echo“
”;}
好的,我稍后会尝试一下,看看是否一切正常。看起来好像一切正常。非常感谢。您将如何访问数据?例如:$reservations[0]['name']谢谢。答案将交给第一响应者,但出于简单起见,我可能最终使用您的答案。您将如何访问数据?例如:$reservations[0]['name']谢谢。答案会交给第一响应者,但出于简单的考虑,我最终可能会使用你的答案。