Php 将用户id传递给嵌套查询

我正在尝试从用户数据库中选择未订阅特定邮件列表的所有用户。如果用户是列表的成员，内部查询将查找该用户，外部查询将选择内部结果为零行的所有用户

SELECT u.userid, u.username, u.mail, u.name, 
    u.lastname, u.starting_year, u.userid AS UIDD 
FROM userdb.users AS u 
WHERE (SELECT COUNT(*) FROM maildb.lists AS l, 
        maildb.list_subscriptions AS s, userdb.users AS u 
    WHERE u.userid = UIDD 
    AND l.listid = '$LIST_ID_TO_LOOKUP' 
    AND s.userid = u.userid 
    AND s.listid = l.listid) = 0 
ORDER BY u.starting_year DESC, u.lastname, u.name;

在我转移到新服务器并更新了许多组件（包括MySQL）之前，这一切都很好

现在，运行此查询时出现错误：

1054-where子句中的未知列“UIDD”

这可能是一个旧语法的问题，现在已经被去除了吗？我现在运行的是MySQL 5.5.24。

您不能这样做

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您可以做的是重写子查询以按u.userid选择列和组，并在sub_select.userid=u.userid上加入此子选择。。其中userid不在子查询中

SELECT 
 u.userid, 
 u.username, 
 u.mail, 
 u.name, 
 u.lastname,
 u.starting_year, 
 u.userid AS UIDD 
FROM 
 userdb.users AS u 
WHERE 
 u.userid NOT IN (
    SELECT 
      u.userid 
    FROM 
      maildb.lists AS l, 
      maildb.list_subscriptions AS s, 
      userdb.users AS u 
    WHERE 
      u.userid = u.userid 
      AND l.listid = '$LIST_ID_TO_LOOKUP' 
      AND s.userid = u.userid 
      AND s.listid = l.listid
    ) 
ORDER BY 
 u.starting_year DESC, u.lastname, u.name;

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@thatidiotguy-不，UIDD在根查询中有别名。工作起来很有魅力：我想知道为什么以前的查询可以工作，但现在不行。