Php Yii框架webservice在postman中上载图像

我正试图上传来自邮递员表单数据的图像。我无法得到输入

 URL: localhost/sampleyii/web-app/web/imageuploads
 Method: POST
 {"Content-Type":"application/x-www-form-urlencoded"}
 Form-data
  id : 2
  image : test.jpg (type:file)   

在我的yii编码中：

 $model = new TblImgUpload(); 
 print_r(Yii::$app->request->post());
 $model->load(Yii::$app->request->post(),'');

邮差回应:

Array
 (
[------WebKitFormBoundarySHaGMA86OHQV87iT
Content-Disposition:_form-data;_name] => "id"

sdfgdfgdf
------WebKitFormBoundarySHaGMA86OHQV87iT
Content-Disposition: form-data; name="wretr"; filename="test.jpeg"
Content-Type: image/jpeg........
....................

我尝试了Content Type=>“多部分/表单数据”。但我无法获得输入请求

我希望post请求输入作为表单数据（文件）作为数组

请帮忙，谢谢

$model->load（）需要具有特定名称的post值。所以在你的邮箱里，“id”必须是“TblImgUpload[id]”，“image”必须是“TblImgUpload[image]”

请注意，“id”和“image”必须作为“safe”属性返回到模型中，否则它们将不会以任何大规模方式加载。

使用或检索上载的文件。有一个很好的例子说明如何实现它

下面是我曾经在REST应用程序中使用过的一段快速代码片段：

控制器：

use Yii;
use yii\web\UploadedFile;
use app\models\UploadImageForm;

class UploadController extends ActiveController
{

  public function actionImage()
  {
      $model = new UploadImageForm(); 

      if (Yii::$app->request->isPost) {
          $model->load(Yii::$app->getRequest()->getBodyParams(), '');
          $model->imageFile = UploadedFile::getInstanceByName('imageFile'); 
          /**
           * Note: when validation fails, returning the model itself 
           * will output the failing rules on a '422' response status.
          **/
          return $model->upload() ?: $model;
      }
  }

}

use Yii;
use yii\helpers\Url;
use yii\web\ServerErrorHttpException;


class UploadImageForm extends \yii\base\Model
{
    public $imageFile;
    public $documentPath = 'uploads/';

    public function rules()
    {
        return [
            [['imageFile'], 'required'],
            [['imageFile'], 'file', 'skipOnEmpty' => false, 'extensions' => 'png, jpg',  'maxSize' => 4194304, 'tooBig' => 'File size limit is 4MB'],
        ];
    }

    public function attributes()
    {
        return ['imageFile'];  
    }


    public function upload()
    {
        if ($this->validate()) {

            $fileName = $this->imageFile->baseName . '.' . $this->imageFile->extension;
            $path = $this->documentPath . Yii::$app->user->id . '/';

            if ($this->imageFile->saveAs($path.$fileName) === false)
                throw new ServerErrorHttpException('Failed for unknown reason. please try again');

            return [
                'imagePath' => Url::to('@web', true) .'/'. $path.$fileName, 
            ];
        } 

        return false;
    }
}

型号：

use Yii;
use yii\web\UploadedFile;
use app\models\UploadImageForm;

class UploadController extends ActiveController
{

  public function actionImage()
  {
      $model = new UploadImageForm(); 

      if (Yii::$app->request->isPost) {
          $model->load(Yii::$app->getRequest()->getBodyParams(), '');
          $model->imageFile = UploadedFile::getInstanceByName('imageFile'); 
          /**
           * Note: when validation fails, returning the model itself 
           * will output the failing rules on a '422' response status.
          **/
          return $model->upload() ?: $model;
      }
  }

}

use Yii;
use yii\helpers\Url;
use yii\web\ServerErrorHttpException;


class UploadImageForm extends \yii\base\Model
{
    public $imageFile;
    public $documentPath = 'uploads/';

    public function rules()
    {
        return [
            [['imageFile'], 'required'],
            [['imageFile'], 'file', 'skipOnEmpty' => false, 'extensions' => 'png, jpg',  'maxSize' => 4194304, 'tooBig' => 'File size limit is 4MB'],
        ];
    }

    public function attributes()
    {
        return ['imageFile'];  
    }


    public function upload()
    {
        if ($this->validate()) {

            $fileName = $this->imageFile->baseName . '.' . $this->imageFile->extension;
            $path = $this->documentPath . Yii::$app->user->id . '/';

            if ($this->imageFile->saveAs($path.$fileName) === false)
                throw new ServerErrorHttpException('Failed for unknown reason. please try again');

            return [
                'imagePath' => Url::to('@web', true) .'/'. $path.$fileName, 
            ];
        } 

        return false;
    }
}

---

嗨，谢谢你的快速回复。我已经尝试了上面的代码并在postman中进行了测试。它不起作用。下面是邮递员对表单数据的回应。{“imageFile”：null}。请帮助？？是的，它应该是

多部分/表单数据

，而不是

x-www-form-urlencoded

<代码>图像文件在我的代码中是应该上载文件的字段的名称。我认为在您的例子中，该字段被称为

wretr

。另外，请尝试取消设置其他字段，我对其了解不多，但

[Content Disposition:\u form-data；\u name]=>“id”

对我来说看起来很奇怪。我可能错了，但我通常认为它是

内容配置：表单数据；name=“id”

我尝试过官方示例和您的示例，但由于某种原因，它们都不能与邮递员一起使用。我一直在Yii端获取imageFile=null，但是如果返回$\u FILES数组，我可以在那里看到我的文件，并且内容类型确实是多部分/表单数据。那真是令人扫兴