如何合并用php编写的两个服务器代码
我有两个用php编写的服务器代码要合并。 第一个代码是使用mysql数据库并在数据库中激发查询并返回结果如何合并用php编写的两个服务器代码,php,mysql,Php,Mysql,我有两个用php编写的服务器代码要合并。 第一个代码是使用mysql数据库并在数据库中激发查询并返回结果 <?php //TODO: show error off require_once("mysql.class.php"); $dbHost = "localhost"; $dbUsername = "root"; $dbPassword = ""; $dbName = "project"; $db = new MySQL($dbHost,$dbUsern
<?php
//TODO: show error off
require_once("mysql.class.php");
$dbHost = "localhost";
$dbUsername = "root";
$dbPassword = "";
$dbName = "project";
$db = new MySQL($dbHost,$dbUsername,$dbPassword,$dbName);
// if operation is failed by unknown reason
define("FAILED", 0);
define("SUCCESSFUL", 1);
// when signing up, if username is already taken, return this error
define("SIGN_UP_USERNAME_CRASHED", 2);
// when add new friend request, if friend is not found, return this error
define("ADD_NEW_USERNAME_NOT_FOUND", 2);
// TIME_INTERVAL_FOR_USER_STATUS: if last authentication time of user is older
// than NOW - TIME_INTERVAL_FOR_USER_STATUS, then user is considered offline
define("TIME_INTERVAL_FOR_USER_STATUS", 60);
define("USER_APPROVED", 1);
define("USER_UNAPPROVED", 0);
$username = (isset($_REQUEST['username']) && count($_REQUEST['username']) > 0)
? $_REQUEST['username']
: NULL;
$password = isset($_REQUEST['password']) ? md5($_REQUEST['password']) : NULL;
$port = isset($_REQUEST['port']) ? $_REQUEST['port'] : NULL;
$action = isset($_REQUEST['action']) ? $_REQUEST['action'] : NULL;
if ($username == NULL || $password == NULL)
{
echo FAILED;
exit;
}
$out = NULL;
error_log($action."\r\n", 3, "error.log");
switch($action)
{
case "authenticateUser":
// code for generating list of shares.
if ($port != NULL
&& ($userId = authenticateUser($db, $username, $password, $port)) != NULL)
{
// providerId and requestId is Id of a friend pair,
// providerId is the Id of making first friend request
// requestId is the Id of the friend approved the friend request made by providerId
// fetching friends,
// left join expression is a bit different,
// it is required to fetch the friend, not the users itself
$sql = "select u.Id, u.username, (NOW()-u.authenticationTime) as authenticateTimeDifference, u.IP,
f.providerId, f.requestId, f.status, u.port
from friends f
left join users u on
u.Id = if ( f.providerId = ".$userId.", f.requestId, f.providerId )
where (f.providerId = ".$userId." and f.status=".USER_APPROVED.") or
f.requestId = ".$userId." ";
if ($result = $db->query($sql))
{
$out .= "<data>";
$out .= "<user userKey='".$userId."' />";
while ($row = $db->fetchObject($result))
{
$status = "offline";
if (((int)$row->status) == USER_UNAPPROVED)
{
$status = "unApproved";
}
else if (((int)$row->authenticateTimeDifference) < TIME_INTERVAL_FOR_USER_STATUS)
{
$status = "online";
}
$out .= "<friend username = '".$row->username."' status='".$status."' IP='".$row->IP."'
userKey = '".$row->Id."' port='".$row->port."'/>";
// to increase security, we need to change userKey periodically and pay more attention
// receiving message and sending message
}
$out .= "</data>";
}
else
{
$out = FAILED;
}
}
else
{
// exit application if not authenticated user
$out = FAILED;
}
break;
case "signUpUser":
if (isset($_REQUEST['email']))
{
$email = $_REQUEST['email'];
$sql = "select Id from users
where username = '".$username."' limit 1";
if ($result = $db->query($sql))
{
if ($db->numRows($result) == 0)
{
$sql = "insert into users(username, password, email)
values ('".$username."', '".$password."', '".$email."') ";
error_log("$sql", 3 , "error_log");
if ($db->query($sql))
{
$out = SUCCESSFUL;
}
else {
$out = FAILED;
}
}
else
{
$out = SIGN_UP_USERNAME_CRASHED;
}
}
}
else
{
$out = FAILED;
}
break;
case "addNewFriend":
$userId = authenticateUser($db, $username, $password);
if ($userId != NULL)
{
if (isset($_REQUEST['friendUserName']))
{
$friendUserName = $_REQUEST['friendUserName'];
$sql = "select Id from users
where username='".$friendUserName."'
limit 1";
if ($result = $db->query($sql))
{
if ($row = $db->fetchObject($result))
{
$requestId = $row->Id;
if ($row->Id != $userId)
{
$sql = "insert into friends(providerId, requestId, status)
values(".$userId.", ".$requestId.", ".USER_UNAPPROVED.")";
if ($db->query($sql))
{
$out = SUCCESSFUL;
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED; // user add itself as a friend
}
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
break;
case "responseOfFriendReqs":
$userId = authenticateUser($db, $username, $password);
if ($userId != NULL)
{
$sqlApprove = NULL;
$sqlDiscard = NULL;
if (isset($_REQUEST['approvedFriends']))
{
$friendNames = split(",", $_REQUEST['approvedFriends']);
$friendCount = count($friendNames);
$friendNamesQueryPart = NULL;
for ($i = 0; $i < $friendCount; $i++)
{
if (strlen($friendNames[$i]) > 0)
{
if ($i > 0 )
{
$friendNamesQueryPart .= ",";
}
$friendNamesQueryPart .= "'".$friendNames[$i]."'";
}
}
if ($friendNamesQueryPart != NULL)
{
$sqlApprove = "update friends set status = ".USER_APPROVED."
where requestId = ".$userId." and
providerId in (select Id from users where username in (".$friendNamesQueryPart."));
";
}
}
if (isset($_REQUEST['discardedFriends']))
{
$friendNames = split(",", $_REQUEST['discardedFriends']);
$friendCount = count($friendNames);
$friendNamesQueryPart = NULL;
for ($i = 0; $i < $friendCount; $i++)
{
if (strlen($friendNames[$i]) > 0)
{
if ($i > 0 )
{
$friendNamesQueryPart .= ",";
}
$friendNamesQueryPart .= "'".$friendNames[$i]."'";
}
}
if ($friendNamesQueryPart != NULL)
{
$sqlDiscard = "delete from friends
where requestId = ".$userId." and
providerId in (select Id from users where username in (".$friendNamesQueryPart."));
";
}
}
if ( ($sqlApprove != NULL ? $db->query($sqlApprove) : true) &&
($sqlDiscard != NULL ? $db->query($sqlDiscard) : true)
)
{
$out = SUCCESSFUL;
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
break;
default:
$out = FAILED;
break;
}
echo $out;
///////////////////////////////////////////////////////////////
function authenticateUser($db, $username, $password, $port)
{
$sql = "select Id from users
where username = '".$username."' and password = '".$password."'
limit 1";
$out = NULL;
if ($result = $db->query($sql))
{
if ($row = $db->fetchObject($result))
{
$out = $row->Id;
$sql = "update users set authenticationTime = NOW(),
IP = '".$_SERVER["REMOTE_ADDR"]."' ,
port = ".$port."
where Id = ".$row->Id."
limit 1";
$db->query($sql);
}
}
return $out;
}
?>
case "filesharing":$base=$_REQUEST['image'];
//echo $base;
$binary=base64_decode($base);
header('Content-Type: bitmap; charset=utf-8');
$file = fopen('uploaded_image'.time().'.jpg', 'wb');
fwrite($file, $binary);
fclose($file);
$out .= "Image upload complete!!, Please check your php file directory……";
break;
有人能给点建议吗？所以你基本上有两个文件，有两个独立的功能。显而易见的解决方案是用一个函数封装每一位代码，即
function query() {
/* your database query code here */
}
function file_upload() {
/* your file upload code here */
}
class MyCoolClass {
function query() {
/* your database query code here */
}
function file_upload() {
/* your file upload code here */
}
}
面向对象编程的优点（和缺点）已经做得很彻底了，只要有一个谷歌，你无疑会发现很多精彩的东西，非常好的资源。问题到底是什么？既然你说两个代码都工作正常，那么这里就没有问题可以回答了。你是在第二个代码中使用第一个代码的输出吗？@Ghomey我必须将这两个代码整合起来files@OMTheEternity我正在开发两个模块：文件共享和聊天应用程序。现在我想将这两个文件集成到一个php文件中。我喜欢你的想法。我是php新手。您能告诉我php如何处理http POST并根据情况调用这些方法吗？可以使用superglobal$\u POST数组从表单获取发布的数据。然后根据数据是什么，调用相关的方法。是的，但是POST和GET是显式的，而请求可能来自不同的来源@Turpachul在阅读了你的链接后，我觉得这个请求更好。等一下。。让我直说吧。。当有人向您的应用程序请求数据时，您应该使用$\u GET。当有人向您的应用程序推送（插入或更新；或删除）数据时，您应该使用$\u POST。就应用程序而言，这意味着只有服务器和mysql？
class MyCoolClass {
function query() {
/* your database query code here */
}
function file_upload() {
/* your file upload code here */
}
}