Php 计数具有多个键的数组中的出现次数
我试图获取包含count 1键值的数组的出现次数,例如:Php 计数具有多个键的数组中的出现次数,php,arrays,counting,Php,Arrays,Counting,我试图获取包含count 1键值的数组的出现次数,例如: $newarray[0] = [ 'id' => '2', 'date' => '2016-04-22' ]; $newarray[1] = [ 'id' => '2', 'date' => '2016-04-13
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-13'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
我想把这个转变成这样:
Array ( [0] => Array ( [id] => 1 [date] => 2016-03-11 [occurences] => 2 ) [1] => Array ( [id] => 2 [date] => 2016-04-22 [occurences] => 4 ) )
我试着这样做:
$cleanarray;
$newarray2=$newarray;
$newarray;
$k=0;
$num=1;
for($i=0; $i<count($newarray); $i++){
for($j=1; $j<count($newarray2); $j++){
if($newarray2[$j]["id"]==$newarray[$i]["id"]){
$num++;
}
}
$cleanarray[$k] = [
'id' => $newarray[$i]["id"],
'date' => $newarray[$i]["date"],
'occurences' => $num
];
$k++;
$num=0;
}
但在这种情况下它不起作用,我怎样才能找到解决方案 您可以按如下方式进行:-
$final_array = array();
foreach($newarray as $arr){
if(!in_array($arr['id'],array_keys($final_array))){
$final_array[$arr['id']] = $arr;
$final_array[$arr['id']]['occurences'] = 1;
}else{
$final_array[$arr['id']]['occurences'] += 1;
}
}
$final_array= array_values($final_array);
print_r($final_array);
function cmpId($a, $b) {
return ($a['id'] - $b['id']);
}
usort($final_array, "cmpId");
print_r($final_array);
输出:-
注意:-如果希望最终数组为id的升序,请使用如下函数:-
$final_array = array();
foreach($newarray as $arr){
if(!in_array($arr['id'],array_keys($final_array))){
$final_array[$arr['id']] = $arr;
$final_array[$arr['id']]['occurences'] = 1;
}else{
$final_array[$arr['id']]['occurences'] += 1;
}
}
$final_array= array_values($final_array);
print_r($final_array);
function cmpId($a, $b) {
return ($a['id'] - $b['id']);
}
usort($final_array, "cmpId");
print_r($final_array);
输出:-您可以按如下方式执行:-
$final_array = array();
foreach($newarray as $arr){
if(!in_array($arr['id'],array_keys($final_array))){
$final_array[$arr['id']] = $arr;
$final_array[$arr['id']]['occurences'] = 1;
}else{
$final_array[$arr['id']]['occurences'] += 1;
}
}
$final_array= array_values($final_array);
print_r($final_array);
function cmpId($a, $b) {
return ($a['id'] - $b['id']);
}
usort($final_array, "cmpId");
print_r($final_array);
输出:-
注意:-如果希望最终数组为id的升序,请使用如下函数:-
$final_array = array();
foreach($newarray as $arr){
if(!in_array($arr['id'],array_keys($final_array))){
$final_array[$arr['id']] = $arr;
$final_array[$arr['id']]['occurences'] = 1;
}else{
$final_array[$arr['id']]['occurences'] += 1;
}
}
$final_array= array_values($final_array);
print_r($final_array);
function cmpId($a, $b) {
return ($a['id'] - $b['id']);
}
usort($final_array, "cmpId");
print_r($final_array);
输出:-我知道您在寻找什么,但我认为这可以解决您的问题:
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
foreach($newarray as $key => $value){
if(isset($found[$value['id']][$value['date']])) {
$found[$value['id']][$value['date']]++;
} else {
$found[$value['id']][$value['date']] = 1;
}
}
print_r($found);
这将返回如下结果:-
Array
(
[2] => Array
(
[2016-04-22] => 1
[2016-04-12] => 2
[2016-03-05] => 1
)
[1] => Array
(
[2016-03-11] => 1
[2016-03-01] => 1
)
)
我知道你在寻找什么,但我认为这可以解决你的问题:
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
foreach($newarray as $key => $value){
if(isset($found[$value['id']][$value['date']])) {
$found[$value['id']][$value['date']]++;
} else {
$found[$value['id']][$value['date']] = 1;
}
}
print_r($found);
这将返回如下结果:-
Array
(
[2] => Array
(
[2016-04-22] => 1
[2016-04-12] => 2
[2016-03-05] => 1
)
[1] => Array
(
[2016-03-11] => 1
[2016-03-01] => 1
)
)
在这个过程中使用临时密钥将是最有效的方法。临时键简化了输出数组任务,需要更少更快的检查。如果要在生成结果数组后按
id
排序,则临时键允许进行简单的ksort()
调用
代码:()
输出:
array (
0 =>
array (
'id' => '1',
'date' => '2016-03-11',
'occurrences' => 2,
),
1 =>
array (
'id' => '2',
'date' => '2016-04-22',
'occurrences' => 4,
),
)
在这个过程中使用临时密钥将是最有效的方法。临时键简化了输出数组任务,需要更少更快的检查。如果要在生成结果数组后按
id
排序,则临时键允许进行简单的ksort()
调用
代码:()
输出:
array (
0 =>
array (
'id' => '1',
'date' => '2016-03-11',
'occurrences' => 2,
),
1 =>
array (
'id' => '2',
'date' => '2016-04-22',
'occurrences' => 4,
),
)
AlivetoDie请参阅我对精简流程的回答。AlivetoDie请参阅我对精简流程的回答。