Php 使用数据库中的值作为索引的多维数组。localhost的输出与webhost不同

前几天我问了这个问题：

我听了他们的回答，把输入放在一个数组中。我只在多维数组中添加了数组，以便可以轻松地操作值。我使用值的主键作为索引。一切都按计划进行了。但是当我将代码放在我们的webhost（philwebhosting）中时，数组输出是不同的。主键索引不起作用，而是使用从0-5开始的默认索引。现在我的代码不再工作了

 <form method="POST" action="custInfo.php">
    <center><input type="submit" id="btn" name="room"></center>
    $query = mysqli_query($conn, "SELECT room_name, room_type, room_rate, inclusive, description, room_status, max_cap
                                        FROM room
                                        WHERE room_status = 'available'");
        if($res = mysqli_query($conn, $query)){ 
        while($row = mysqli_fetch_assoc($res)){
            if($row['available_rooms'] != 0){
                echo "<div class='chooseRoom'>";
                echo "<div class='indent'>";
                echo "<h4>".$row['room_type']."</h4>";
                echo "<h5>".$row['room_rate']."php</h5>";
                echo "<img src='../images/".$row['room_type'].".jpg' width=250 height=160>";
                /*unfinished choosing of room type*/
                echo "<h5><input type='checkbox' name='roomType[".$row['roomDetailsNo']."][]' value='".$row['roomDetailsNo']."'> Choose this Room";
                /*unfinished number of rooms*/
                echo "&nbsp;&nbsp;&nbsp;Number of Rooms:&nbsp;";
                echo "<select name='noOfRooms[".$row['roomDetailsNo']."][]'>";
                $ctr1 = 0;
                while($ctr1 <= $row['available_rooms']){
                echo "<option>";
                echo $ctr1;
                echo "</option>";
                $ctr1++;
                }
                echo "</select><br>";
                /*Number of Guests*/
                echo "<br>Number of Adult:&nbsp;";
                echo "<select name='adult[".$row['roomDetailsNo']."][]'>";
                $ctr2 = 0;
                while($ctr2 <= $row['max_cap']){
                echo "<option>";
                echo $ctr2;
                echo "</option>";
                $ctr2++;
                }
                echo "</select>";
                echo "&nbsp;&nbsp;&nbsp;Number of Children:&nbsp;";
                echo "<select name='children[".$row['roomDetailsNo']."][]'>";
                echo "<option>0</option>";
                echo "<option>1</option>";
                echo "<option>2</option>";
                echo "<option>3</option>";
                echo "<option>4</option>";
                echo "<option>5</option>";
                echo "</select><br>";
                echo "</h5>";
                echo "<table class='table'>";
                echo "<thead>";
                echo "<th>Inclusive</th><th>Description</th>";
                echo "</thead>";
                echo "<tbody>";
                echo "<td>".$row['inclusive']."</td><td>".$row['description']."</td>";
                echo "</tbody>";
                echo "<tfoot>";
                echo "<td colspan='2'>";
                echo $row['room_status'];
                echo "</td>";
                echo "</tfoot>";
                echo "</table>";
                echo "</div>";
                echo "</div>";
            }
            else{
                echo "No rooms available in the date you desire!";
            }
        }
    }
    else{
        die("ERROR: ".mysqli_error($conn));
    }

        </form>

---

顺便说一句，我将此代码添加到下一页，因为我的代码应该添加我在localhost中获得的儿童数量和成人数量的值。

请显示生成的表单html如何将$number变量设置为$row['roomDetailsNo']因为您没有从db中选择roomDetailsNo？很好，请点击@Jiboulex抱歉。忘记删除$number变量。这是我第一次尝试创建代码的一部分。这是生成的表单。请显示为表单生成的html。如果不从db中选择roomDetailsNo，如何使用$row['roomDetailsNo']设置$number变量？很好，请点击@Jiboulex抱歉。忘记删除$number变量。这是我第一次尝试创建代码的一部分。这是生成的表单

echo "<pre>";
print_r($_POST);
echo "</pre>";

    $query = ("SELECT COUNT(rooms.roomDetailsNo) AS available_rooms, roomDetails.roomDetailsNo, roomDetails.room_type, roomDetails.room_rate, rooms.room_status, roomDetails.room_pax, roomDetails.max_cap
                FROM rooms
                LEFT JOIN roomDetails
                ON roomDetails.roomDetailsNo = rooms.roomDetailsNo
                WHERE room_status = 'available'
                GROUP BY room_type;");

$adult = 0;
$children = 0;
$noOfRooms = 0;
if($res = mysqli_query($conn, $query)){ 
    while($row = mysqli_fetch_assoc($res)){
        $adult += $_POST['adult'][$row['roomDetailsNo']][0];
        $children += $_POST['children'][$row['roomDetailsNo']][0];
        $noOfRooms += $_POST['noOfRooms'][$row['roomDetailsNo']][0];
    }
}

$_SESSION['adult'] = $adult;
$_SESSION['children'] = $children;
$_SESSION['noOfRooms'] = $noOfRooms;