PHP邮件发送具有不同时间戳的副本
我的网站上有一个PHP/AJAX表单(点击请求项目) 当我在多台计算机上测试表单时,它对我来说运行良好。但是,我会偶尔收到一封重复的电子邮件,并且至少有一位试图提交的用户告诉我,这封电子邮件给了他们一个警报错误,我无法复制 这就是我正在使用的PHP。是否有任何突出的潜在问题PHP邮件发送具有不同时间戳的副本,php,Php,我的网站上有一个PHP/AJAX表单(点击请求项目) 当我在多台计算机上测试表单时,它对我来说运行良好。但是,我会偶尔收到一封重复的电子邮件,并且至少有一位试图提交的用户告诉我,这封电子邮件给了他们一个警报错误,我无法复制 这就是我正在使用的PHP。是否有任何突出的潜在问题 <?php //Retrieve form data. //GET - user submitted data using AJAX //POST - in case user does not support j
<?php
//Retrieve form data.
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$subject = ($_GET['subject']) ?$_GET['subject'] : $_POST['subject'];
$comments = ($_GET['comments']) ?$_GET['comments'] : $_POST['comments'];
//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.';
if (!$subject) $errors[count($errors)] = 'Please choose a subject.';
if (!$comments) $errors[count($errors)] = 'Please enter your comments.';
//if the errors array is empty, send the mail
if (!$errors) {
//recipient
$to = 'brianrhea@gmail.com';
//sender
$from = $name . ' <' . $email . '>';
//subject and the html message
$subject = 'Comment from ' . $name;
$message = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head></head>
<body>
<table>
<tr><td>Name</td><td>' . $name . '</td></tr>
<tr><td>Email</td><td>' . $email . '</td></tr>
<tr><td>Subject</td><td>' . $subject . '</td></tr>
<tr><td>Comments</td><td>' . nl2br($comments) . '</td></tr>
</table>
</body>
</html>';
//send the mail
$result = sendmail($to, $subject, $message, $from);
//if POST was used, display the message straight away
if ($_POST) {
if ($result) echo 'Thank you! We have received your message.';
else echo 'Please verify that you have entered a valid email address.';
//else if GET was used, return the boolean value so that
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
echo $result;
}
//if the errors array has values
} else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="form.php">Back</a>';
exit;
}
//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";
$result = mail($to,$subject,$message,$headers);
if ($result) return 1;
else return 0;
}
?>
此代码似乎不会发送两次邮件
- 尝试搜索应用程序中调用此代码/函数的其他位置李>
- 还应检查是否有刷新预防措施—是否检测到ajax请求使用相同的数据非常及时地发送,或者是否存在某种双击使用情况
谢谢Elzo,我会查一下的。你能成功提交表单吗?事实上,如果用户足够快,可以点击两次按钮,那么事件有可能被触发不止一次。我意识到这是什么。提交后未清除表单数据。因此,如果用户出于某种原因刷新页面,它将重新提交表单。我需要找到一种方法,让表单输入在提交后清除,然后我想我会被设置好。谢谢你的帮助!使用$\u REQUEST可能更容易一些:一个关联数组,默认情况下包含$\u GET、$\u POST和$\u COOKIE的内容。仅供参考,您不需要验证$\u GET/$\u POST,您应该根据用户输入进行验证