Php 删除json中的括号?
对于json处理,如何去掉下面的括号Php 删除json中的括号?,php,json,Php,Json,对于json处理,如何去掉下面的括号 [{"success":true,"filename":"bialding_and_rebialding_plymouth02.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth03.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth04.jpg"}] 上面的结果由下面的类处理成一个数组 fun
[{"success":true,"filename":"bialding_and_rebialding_plymouth02.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth03.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth04.jpg"}]
上面的结果由下面的类处理成一个数组
function handle_upload($upload_directory)
{
# Loop the code according to the number of files.
for($i = 1; $i <= $this->total; $i++)
{
...
if ($this->file->save($upload_directory.$name_filtered.'.'.$file_extension , $i-1))
{
$message[] = array('success'=>true,'filename'=>$name_filtered.'.'.$file_extension);
}
else
{
$message[] = array('error'=> 'Could not save uploaded file.' . 'The upload was cancelled, or server error encountered');
}
}
return $message;
}
但我只需要在我的结果中,不带括号
{"success":true,"filename":"bialding_and_rebialding_plymouth02.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth03.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth04.jpg"}
str_replace(数组('[',']'),'',htmlspecialchars(json_encode($result),ENT_NOQUOTES))代码>?通过在函数中执行以下操作,可以拉出json并返回它:
return $message[0]; // only json
或者,您可以将其全部退回,然后将其删除:
$uploader = new uploader();
$result1 = $uploader->handle_upload('uploads/');
$result2 = $result[0];
如果没有括号,json字符串将无效。JSON字符串只能包含一个值。加上括号,它是一个数组或对象。没有括号,它是一系列单独的逗号分隔对象-无效。这不再是有效的json。为什么不使用[]
?你将如何处理生成的字符串?我的错误-我认为括号应该在那里。我是json新手-对不起@lauthiamkok:括号应该在那里,否则无效。好家伙,tks!!
$uploader = new uploader();
$result1 = $uploader->handle_upload('uploads/');
$result2 = $result[0];