Php 获取两个Id'；来自内部连接的s

我在php Codeigniter框架中的一个网站上工作，在将表连接在一起时遇到问题

这两张桌子是餐点和餐厅，只是简单的版本

meals: id, restaurant_id, price, etc.

restaurants: id, name, location, etc.

要进行查询，我使用以下代码：

$this->db->join('restaurants', 'restaurants.id = meals.restaurant_id');
$query = $this->db->get('meals');

返回与运行此操作相同的结果：

$query = $this->db->query('SELECT * FROM meals INNER JOIN restaurants ON restaurants.id = meals.restaurant_id'); 

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问题是，当我以php数组或and对象（由codeigniter DB类提供）的形式访问结果时，只返回一个id，即餐厅id，我需要餐食id。我如何让它吐出餐食id？

我对您当前的工具（php/codeigniter/等）没有经验，我假设出现问题是因为两个表的“id”列的名称相同？（这通常不是问题……但可能工具处理得不正确？）对于SQL查询，区分同名列的一种方法是在select语句中使用别名。以下是一个例子：

select
    m.id as meal_id,
    m.price as meal_price,
    r.id as restaurant_id,
    r.name as restaurant_name,
    r.location as restaurant_location
from meals as m
inner join restaurants as r on r.id = m.restaurant_id

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我对您当前的工具（php/codeigniter/等等）没有经验，我假设问题的出现是因为两个表的“id”列的名称相同？（这通常不是问题……但可能工具处理得不正确？）对于SQL查询，区分同名列的一种方法是在select语句中使用别名。以下是一个例子：

select
    m.id as meal_id,
    m.price as meal_price,
    r.id as restaurant_id,
    r.name as restaurant_name,
    r.location as restaurant_location
from meals as m
inner join restaurants as r on r.id = m.restaurant_id

试试这个

SELECT t1.id as mid,t2.id as rid
  FROM table_meals as t1
  inner JOIN table_restaurant as t2 ON t2.id = t1.`restaurant_id`

试试这个

SELECT t1.id as mid,t2.id as rid
  FROM table_meals as t1
  inner JOIN table_restaurant as t2 ON t2.id = t1.`restaurant_id`

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谢谢你。结果发现有人用相同的解决方案遇到了完全相同的问题：谢谢你。结果发现有人用相同的解决方案遇到了完全相同的问题：