Php MySql错误：结果由多行组成

我有一个错误：

结果由多行组成，但我找不到它。

条目id_用户在其表中只有一条记录

程序如下：

CREATE DEFINER=`root`@`localhost` PROCEDURE `delete_user_deep`(id_user int(11))
BEGIN

declare nome_loc varchar(45);
declare cognome_loc varchar(45);

select nome,cognome
into nome_loc,cognome_loc
from user
where id_user=id_user;

delete from Radius.radcheck where username in (
    select mac_address from machine where id_user =id_user);

delete from Radius.radreply where username in (
    select mac_address from machine where id_user =id_user);

delete from machine_ip where id_machine in (
    select id_machine from machine where id_user=id_user);

delete from machine where id_user = id_user;

delete from document where id_user=id_user;

delete from user where id_user=id_user;

insert into log_generic values(
                    NULL,
                    'USER',
                    'Delete User Deep',
                    (select concat ('User: ',id_user,' Name: ',cognome_loc,' Prename: ',nome_loc)),
                    now());

END

---

问题在于这句话：

select nome,cognome
into nome_loc,cognome_loc
from user
where id_user=id_user;

如果有多行，这将返回一个错误。错误记录在案

这是因为参数名与列名相同。

id\u用户

指的是比较两侧的列

查询应该如下所示：

select nome, cognome
into nome_loc, cognome_loc
from user
where id_user = param_id_user;

---

始终在参数名和变量名前面加上前缀，以区别于列名。

这是MySQL代码，所以我要删除sql server标记。选中

select concat（'User:'，id_User，'Name:'，cognome_loc，'Prename:'，nome_loc）

如果我去那里，我不会从这里开始。是的，戈登，我检查了它，发现了这个问题，我将id\u user替换为id\u user\u in，它就工作了！非常感谢你