Php 从SQL结果集创建更复杂的json对象

您好，我正在从sql返回一些数据，并希望将其格式化为Json。我知道我可以使用Json.encode（），但数据有点嵌套，我不确定如何实现这一点

这就是我希望json的外观

[
{"coords":
            {"lat":53.745,"lng":-0.338},
                "iconImage":"https://developers.google.com/maps/documentation/javascript/examples/full/images/beachflag.png",
                    "content":"<h1>Tony G</h1>"},
{"coords":{"lat":53.747,"lng":-0.340},
    "iconImage":"https://maps.gstatic.com/mapfiles/ms2/micons/blue.png",
        "content":"<h1>fred</h1>"}
]

[
{“协调”：
{“lat”：53.745，“lng”：-0.338}，
“图像”：https://developers.google.com/maps/documentation/javascript/examples/full/images/beachflag.png",
“内容”：“Tony G”}，
{“coords”：{“lat”：53.747，“lng”：-0.340}，
“图像”：https://maps.gstatic.com/mapfiles/ms2/micons/blue.png",
“内容”：“fred”}
]

这是到目前为止我的代码

require("../PHP/phpsqlajax_dbinfo.php");
$connection=odbc_connect($database, $username, $password);

//Select Test statement 
$query="select 53.745 as lat,-0.338 as lng,'https://developers.google.com/maps/documentation/javascript/examples/full/images/beachflag.png' as iconImage, '<h1>Tony G</h1>' as content union all
select 53.745 as lat,-0.310 as lng,'https://maps.gstatic.com/mapfiles/ms2/micons/blue.png' as iconImage, '<h1>fred</h1>' as content ";

$result=odbc_exec($connection,$query);
//work through result and create JSON
while (odbc_fetch_row($result)){

//what do I do here?

} 

echo json_encode(//theData I would like to return) ;    

require（“../PHP/phpsqlajax_dbinfo.PHP”）；
$connection=odbc\u connect（$database、$username、$password）；
//选择测试语句
$query=“选择53.745作为lat，-0.338作为lng，”https://developers.google.com/maps/documentation/javascript/examples/full/images/beachflag.png“作为我的形象，'托尼G'作为内容联盟所有人”
选择53.745作为lat，-0.310作为lng，'https://maps.gstatic.com/mapfiles/ms2/micons/blue.png'作为图像，'弗雷德'作为内容'；
$result=odbc\u exec（$connection，$query）；
//处理结果并创建JSON
while（odbc_fetch_行（$result））{
//我在这里干什么？
} 
echo json_encode（//我想返回的数据）；

---

感谢您的帮助

只需添加到数组，然后编码：

$json = [];

while ($row = odbc_fetch_row($result)){

    $json[] = [
        'coords' => ['lat' => $row['lat'],'lng' => $row['lng']],
        'iconImage' => $row['iconImage'],
        'content' => $row['content'],
    ];
}

echo json_encode($json);

---

只需添加到数组中，然后编码：

$json = [];

while ($row = odbc_fetch_row($result)){

    $json[] = [
        'coords' => ['lat' => $row['lat'],'lng' => $row['lng']],
        'iconImage' => $row['iconImage'],
        'content' => $row['content'],
    ];
}

echo json_encode($json);