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Php Symfony2:将ArrayCollection转换为文件_Php_File_Symfony_Doctrine Orm_Arraycollection - Fatal编程技术网

Php Symfony2:将ArrayCollection转换为文件

Php Symfony2:将ArrayCollection转换为文件,php,file,symfony,doctrine-orm,arraycollection,Php,File,Symfony,Doctrine Orm,Arraycollection,尝试存储具有多个文件输入的表单时出错 我有两个实体:Inquiry和uploadedDocMend,它们是一对多关系 以下是上传文件的转换器: public function reverseTransform($uploadedDocuments) { $attachments = array(); foreach($uploadedDocuments as $file){ if($file) { $uploadedDocument = n

尝试存储具有多个文件输入的表单时出错

我有两个实体:Inquiry和uploadedDocMend,它们是一对多关系

以下是上传文件的转换器:

public function reverseTransform($uploadedDocuments)
{
    $attachments = array();
    foreach($uploadedDocuments as $file){
        if($file) {
            $uploadedDocument = new UploadedDocument();
            /* @var $uploadedDocument UploadedDocument */
            $uploadedDocument->setFile($file);
            $uploadedDocument->setCreatedOn(new \DateTime("now"));
            $this->em->persist($uploadedDocument);
            $attachments[] = $uploadedDocument;
        }
    }
    return $attachments;
}
下面是添加变压器的代码:

->add($builder->create(
                'uploadedDocuments', 'file', [
                    'required' => false,
                    'multiple' => true,
                    'label' => "Anhänge"
            ]
        )->addModelTransformer(new UploadsTransformer($this->em)))
由此,我得到以下例外情况:

表单的视图数据应该是Symfony\Component\HttpFoundation\File\File类的实例,但却是doctor\Common\Collections\ArrayCollection类的实例。您可以通过将“data_class”选项设置为null或添加一个视图转换器来避免此错误,该转换器将类Doctrine\Common\Collections\ArrayCollection的实例转换为Symfony\Component\HttpFoundation\File\File的实例

我无法更改解析程序。因为我需要这样。我想

public function setDefaultOptions(OptionsResolverInterface $resolver) {
    $resolver->setDefaults(array(
        'data_class' => 'Lengoo\FormhandlerBundle\Entity\Inquiry',
    ));
}
如何更改转换器以正确创建对象? 仅供参考:如果我只存储从文件到数组的路径,它就可以工作。但我想知道这两个物体之间的关系