Php 嵌套数组中的子级递归计数+;通过引用更改值

Php 嵌套数组中的子级递归计数+;通过引用更改值,php,arrays,recursion,reference,Php,Arrays,Recursion,Reference,我知道这是基本的递归,但我还是被卡住了:( 我需要计算每个元素下面有多少个元素(子元素、孙子元素等等),并将该值写入原始数组 我的示例阵列: $table = [ 1 => [ 'id' => 1, 'children_count' => 0 ], 2 => [ 'id' => 2, 'children_count' => 0, 'children' => [ 3 => [

我知道这是基本的递归,但我还是被卡住了:(

我需要计算每个元素下面有多少个元素(子元素、孙子元素等等),并将该值写入原始数组

我的示例阵列:

$table = [
1 => [
    'id' => 1,
    'children_count' => 0
],
2 => [
    'id' => 2,
    'children_count' => 0,
    'children' => [
        3 => [
            'id' => 3,
            'children_count' => 0,
            'children' => [
                4 => [
                    'id' => 4,
                    'children_count' => 0,
                    'children' => [
                        5 => [
                            'id' => 5,
                            'children_count' => 0
                        ],

                        6 => [
                            'id' => 6,
                            'children_count' => 0
                        ]
                    ]
                ]
            ]
        ]
    ]
]    
];
我的递归代码:

function count_children(&$array){
    foreach($array['children'] as &$child){
        if(isset($child['children'])){
            $array['children_count'] += count_children($child);
        }
        else return 1;
    }
}
要求递归:

//call for each root element
foreach($table as &$element){
    if(isset($element['children'])) count_children($element);
}
预期产出:

$table = [
1 => [
'id' => 1,
'children_count' => 0
 ],
 2 => [
'id' => 2,
'children_count' => 4,
'children' => [
    3 => [
        'id' => 3,
        'children_count' => 3,
        'children' => [
            4 => [
                'id' => 4,
                'children_count' => 2,
                'children' => [
                    5 => [
                        'id' => 5,
                        'children_count' => 0
                    ],

                    6 => [
                        'id' => 6,
                        'children_count' => 0
                    ]
                ]
            ]
        ]
    ]
]
]    
];
我哪里弄错的? 我的函数做了一些事情,元素3得到值1,但仅此而已


这是ideone链接:

children\u count是否也有子女或孙子的计数?是的,对不起,我的不好。将此添加到OP..Post您的预期输出@SubjectXelement 7有3个子女?这是一个问题吗?不,是的,但您的示例计数了3个子女:(我想你已经得到了你想要的@SubjectX good one splash58+1是的,它很有效。从我上学的时候起,我就认为它可以短一些,但它不起作用.)。。
function count_children(&$table){
  $count1 = 0;
  foreach($table as &$array) {
    $count = 0;
    if (isset($array['children'])) {
      $count += count($array['children']);
      $count += count_children($array['children']);
    }
    $array['children_count'] = $count;
    $count1 += $count;
  }
  return $count1; 
}

count_children($table);

print_r($table);