Php MySql如何从一个时间间隔生成一个完整的日历？

我是mysql程序的新手。我请求您帮助生成一个带有某种程序的日历（每隔一天生成一行）。。。在stackoverflow上，我找到了以下函数：

CREATE PROCEDURE filldates(dateStart DATE, dateEnd DATE)
    BEGIN

          WHILE dateStart <= dateEnd DO
            INSERT INTO mytable (mydate) VALUES (dateStart);
            SET dateStart = date_add(dateStart, INTERVAL 1 DAY);
          END WHILE;
        END;


    CALL filldates('2014-01-01','2014-12-31');

如果您知道如何生成此类表格，我将非常感激

其他mysql信息

innodb_version : 5.5.35-rel33.0
protocol_version : 10
slave_type_conversions 
version : 5.5.35-33.0-log
version_comment: Percona Server (GPL), Release rel33.0, Revision 61...
version_compile_machine : x86_64
version_compile_os : Linux

---

假设您的表至少有以下

CREATE table

语句：

CREATE mytable(
  ID INT,
  date DATE,
  Price INT
);

INSERT INTO mytable (ID, date, Price)
SELECT
    t.n, 
    DATE_ADD('2014-01-01', INTERVAL t.n DAY),
    40
FROM (
    SELECT 
        a.N + b.N * 10 + c.N * 100 AS n
    FROM
        (SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
       ,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
       ,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4) c
    ORDER BY n
) t   
WHERE
    t.n <= TIMESTAMPDIFF(DAY, '2014-01-01', '2014-12-31');

然后，您可以使用以下语句为一年中的每一天插入行：

CREATE mytable(
  ID INT,
  date DATE,
  Price INT
);

INSERT INTO mytable (ID, date, Price)
SELECT
    t.n, 
    DATE_ADD('2014-01-01', INTERVAL t.n DAY),
    40
FROM (
    SELECT 
        a.N + b.N * 10 + c.N * 100 AS n
    FROM
        (SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
       ,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
       ,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4) c
    ORDER BY n
) t   
WHERE
    t.n <= TIMESTAMPDIFF(DAY, '2014-01-01', '2014-12-31');

---

您好，谢谢您的帮助…我将您的代码粘贴到PhpMyAdmin上的SQL“Tab”中，但结果出现以下错误：#1064-您的SQL语法有错误；查看与您的MySQL服务器版本对应的手册，了解在“DATE_ADD”（'2014-07-01'，INTERVAL t.n DAY'）附近使用的正确语法，我在select的第一行漏掉了一个逗号，现已修复。还有另一个输入错误，添加了fiddle。Ok似乎有效，但我与此有冲突#1136-“第1行的列计数与值计数不匹配”，您能做些什么只生成日期列值吗？将来我想使用相同的ID。感谢您的建议：DMy bad，我删除了不需要的列，留下了一个逗号，和第一次尝试的错误相同。现在更正。该睡觉了！谢谢你们男人们：D工作得很有魅力！