Python 2.7 如何使代码跳到if语句中的某一点

我正在做一个基本的游戏。我想知道如何使代码转到code/if语句中的特定点，而不是从一开始就开始

例如，在我的代码第19行：

kithcn（）

我不想将它重定向到if语句的开头；再次进入描述厨房，然后要求输入：

choice02=raw\u input（“你做什么？”）

，但我希望它直接跳到输入部分

def kitchen():
    print "You see a dusty old kitchen, nobody has probably used it for quite a while."
    print "There are 3 different cupboards(0, 1, 2) or a letter(3) placed on the counter."
    choice02 = raw_input("What do you do? >")

    if choice02 == "0" or choice02 == "first cupboard" or choice02 == "check first cupboard" or choice02 == "open first cupboard":
        print "You see a dusty empty bottles of milks, with spiderwebs at the corners of the cupboard. Nothing of Interest here."
        raw_input(">")
        kitchen()

    elif choice02 == "1" or choice02 == "second cupbaord" or choice02 == "check second cupboard" or choice02 == "open second cupboard":
        print "You see some packs of likely expired cereal and a key(0)."
        choice_02_A = raw_input("What do you do? >")

   #----------------------------------------------------------------------------------------------------------#
        if choice02_A == "pick key" or choice02_A == "key" or choice02_A == "0" or choice02_A == "get key":
            print "You picked the key. This probably unlocks some door."
            raw_input("> ")
            kitchen()

        elif choice02_A == "close cupboard" or choice02_A == "kitchen" or choice02_A == "go back to kitchen":
            kitchen()

        else:
            print "Not a valid option."
   #-----------------------------------------------------------------------------------------------------------#

    elif choice02 == "2" or choice02 == "third cupboard" or choice02 == "check third cupboard" or choice02 == "open third cupboard":
        print "You see an empty or dusty cupboard. Nothing of interest here."
        raw_input("> ")
        kitchen()

    elif choice02 == "3" or choice02 == "check letter" or choice02 == "letter" or choice02 == "read letter":
        print """
        You read the letter:
        \n"Dear Shawn............\n"
        It makes no sense to you.
        """


    elif choice02 == "go back" or choice02 == "entrance hall" or choice02 == "go to entrance hall":
        entrance_hall()

else:
    "Not a valid Option."

---

我看不到循环，但如果您在从外部调用函数时只需要print语句，则可以使用如下可选布尔值：

def kitchen(already_there=False):
    if not already_there:
        print('...')
    choice02 = raw_input("What do you do? >")

    # ...

    elif # ...
        # ...
        kitchen(already_there=True)

---

您可能需要考虑重构代码并使用字典避免长IF语句。

看

---

适当缩进你的代码同样，你在问题中不断地说“循环”。什么循环？对不起，我的错，我是新来的。一个误解，不管怎样，我做了一个编辑。复印时缩进有点乱。不用担心。另外，请缩进。目前的代码不是有效的Python。特别是，在

def

之后的所有内容都需要升级一级。这特别好，因为它与您已经编写的任何代码都向后兼容。好的，谢谢！这肯定更干净。尽管我如何为一个值/stringHmm分配多个键，但一种可能性是使用两个字典。一个用于存储别名密钥关联，另一个用于存储实际数据。我很快会更新我的答案。

print "There are 3 different cupboards(0, 1, 2) or a letter(3) placed on the counter." 

alias = {
  '0': '0',
  'first cupboard': '0',
  'check first cupboard': '0',
  'open first cupboard': '0',
  '1': '1',
  'second cupboard': '1',
  'check second cupboard':'1',
  ...
}

dic = {
  "0":"You see a dusty empty bottles of milks, with spiderwebs at the corners of the cupboard. Nothing of Interest here.",  \
  "1":"You see some packs of likely expired cereal and a key(0).",  \
  "2":"You see an empty or dusty cupboard. Nothing of interest here."
  ...
}

while(True):
  choice02 = raw_input("What do you do? >")
  if choice02 in alias:
    print dic[alias[choice02]]
    break
  else:
    print "Not a valid option"