Python 2.7 在python2.7中将列表堆叠到数组中

我正在尝试解决如何将多个列表添加到一个数组中。下面是我想到的，但它不起作用

import math
import numpy as np

myList1 = [1,2,'nan']
myList2 = [3,4,5]

class myThing(object):
    def __init__(self, myLists=[]): #This could accept 1 or many lists
    self.__myVars = np.array(myLists, dtype=float)
    self.__myVars.shape = (len(myLists),3)
    self.__myVars = np.vstack(myVars)

        @property
    def myVars(self):
        return self.__myVars

foo = myThing(myList1,myList2)
print foo.myVars

blah blah...
TypeError: __init__() takes at most 2 arguments (3 given)

帮助

在def\uu init\uuuuu中允许\uu init\uuu接受任意数量的参数：

def __init__(self, *myLists): #This could accept 1 or many lists

def __init__(self, *myLists): #This could accept 1 or many lists

屈服

[[  1.   2.  nan]
 [  3.   4.   5.]]

此外，在调试错误时，查看异常本身以外的内容也很有用。完整回溯包括发生异常的行：

---> 20 foo = myThing(myList1,myList2)
     21 print foo.myVars

TypeError: __init__() takes at most 2 arguments (3 given)

这有助于我们了解问题的原因。

我想你的意思是：

def __init__(self, *myLists): #This could accept 1 or many lists