Python 3.x 为什么第二次迭代总是失败？

我试图通过基于五个位置过滤数据帧来创建z_分数的dict

无论列表中的第一个位置是哪个，我总是将第一个key:value对放入 无论哪个位置是第二个，我总是会得到这个错误：

Traceback (most recent call last):
  File "C:\Program Files\JetBrains\PyCharm 2018.2.1\plugins\python\helpers\pydev\pydevd.py", line 1434, in _exec
    pydev_imports.execfile(file, globals, locals)  # execute the script
  File "C:\Program Files\JetBrains\PyCharm 2018.2.1\plugins\python\helpers\pydev\_pydev_imps\_pydev_execfile.py", line 18, in execfile
    exec(compile(contents+"\n", file, 'exec'), glob, loc)
  File "C:/Users/Mark/PycharmProjects/main/main.py", line 104, in <module>
    z_score = z_score(base, df['SalePrice'])
TypeError: 'numpy.float64' object is not callable

---

在python中，解释器在局部作用域中对变量名的优先级高于方法名，因此当您使用

z_score

作为变量名时，如果您更改

z_score

变量的名称，它会屏蔽对

z_score

方法名的访问，您的代码应该运行。

尝试使用一个不是'z_score

的变量名，python混淆了浮点值

z_score`和方法名

z_score

。就是这样。非常感谢。听起来不错，我回答了

    def z_score(val, array, bessel=0):
        mean = array.mean()
        st_dev = std(array, ddof=bessel)
        distance = val - mean
        z = distance / st_dev

        return z


    neighborhoods = ['NAmes', 'CollgCr', 'OldTown', 'Edwards', 'Somerst']

    base = 200000
    z_scores = {}
    for neighborhood in neighborhoods:
        df = houses.loc[houses['Neighborhood'] == neighborhood]
        z_score = z_score(base, df['SalePrice'])
        z_scores[neighborhood] = z_score


    sorted_z_scores = sorted(z_scores.items(), key=lambda x: x[1], reverse=True)
    print(sorted_z_scores)