Python PyQt中QLabel的刷新对话框
我正在测试Qlabel的更新。我基本上是以随机顺序显示问题,但标签的旧文本仍然显示并与新文本组合。我不知道如何在“确定”点击之间清除它Python PyQt中QLabel的刷新对话框,python,pyqt,pyqt5,qlabel,Python,Pyqt,Pyqt5,Qlabel,我正在测试Qlabel的更新。我基本上是以随机顺序显示问题,但标签的旧文本仍然显示并与新文本组合。我不知道如何在“确定”点击之间清除它 from PyQt5.QtCore import * from PyQt5.QtGui import * from PyQt5.QtWidgets import * import sys import random class GameDialog(QDialog): def __init__(self): QDialog.__init
from PyQt5.QtCore import *
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
import sys
import random
class GameDialog(QDialog):
def __init__(self):
QDialog.__init__(self)
layout = QGridLayout()
lblWBS = QLabel("lblWBS")
lblDialog = QLabel("lblDialog")
btnOK = QPushButton("OK")
layout.addWidget(btnOK, 5, 1)
def randomOptions():
rdmOpt = [2,3,4]
random.shuffle(rdmOpt)
optGreen = QRadioButton()
optYellow = QRadioButton()
optRed = QRadioButton()
lblGreen = QLabel("Green")
lblYellow = QLabel("Yellow")
lblRed = QLabel("Red")
layout.addWidget(lblWBS, 0, 1)
layout.addWidget(lblDialog, 1, 1)
layout.addWidget(optGreen, rdmOpt[0], 0)
layout.addWidget(lblGreen, rdmOpt[0], 1)
layout.addWidget(optYellow, rdmOpt[1], 0)
layout.addWidget(lblYellow, rdmOpt[1], 1)
layout.addWidget(optRed, rdmOpt[2], 0)
layout.addWidget(lblRed, rdmOpt[2], 1)
self.setLayout(layout)
randomOptions()
btnOK.clicked.connect(randomOptions)
self.setWindowTitle("PALCDMS")
app = QApplication(sys.argv)
dialog = GameDialog()
dialog.show()
app.exec_()
实现你的想法的方法你有错误,因为你正在创建新的对象 您应该保存将更改位置的小部件列表,并在进行更改之前使用
removeWidget()
将其删除,然后将其放回布局中
class GameDialog(QDialog):
def __init__(self):
QDialog.__init__(self)
layout = QGridLayout(self)
lblWBS = QLabel("lblWBS")
lblDialog = QLabel("lblDialog")
btnOK = QPushButton("OK")
layout.addWidget(btnOK, 5, 1)
optGreen = QRadioButton()
optYellow = QRadioButton()
optRed = QRadioButton()
lblGreen = QLabel("Green")
lblYellow = QLabel("Yellow")
lblRed = QLabel("Red")
layout.addWidget(lblWBS, 0, 1)
layout.addWidget(lblDialog, 1, 1)
l = [optGreen, lblGreen, optYellow, lblYellow, optRed, lblRed]
def randomOptions():
for w in l:
layout.removeWidget(w)
rdmOpt = [2,3,4]
random.shuffle(rdmOpt)
for i in range(len(l)):
layout.addWidget(l[i], rdmOpt[i//2], i % 2)
randomOptions()
btnOK.clicked.connect(randomOptions)
self.setWindowTitle("PALCDMS")
实现你的想法的方法你有错误,因为你正在创建新的对象 您应该保存将更改位置的小部件列表,并在进行更改之前使用
removeWidget()
将其删除,然后将其放回布局中
class GameDialog(QDialog):
def __init__(self):
QDialog.__init__(self)
layout = QGridLayout(self)
lblWBS = QLabel("lblWBS")
lblDialog = QLabel("lblDialog")
btnOK = QPushButton("OK")
layout.addWidget(btnOK, 5, 1)
optGreen = QRadioButton()
optYellow = QRadioButton()
optRed = QRadioButton()
lblGreen = QLabel("Green")
lblYellow = QLabel("Yellow")
lblRed = QLabel("Red")
layout.addWidget(lblWBS, 0, 1)
layout.addWidget(lblDialog, 1, 1)
l = [optGreen, lblGreen, optYellow, lblYellow, optRed, lblRed]
def randomOptions():
for w in l:
layout.removeWidget(w)
rdmOpt = [2,3,4]
random.shuffle(rdmOpt)
for i in range(len(l)):
layout.addWidget(l[i], rdmOpt[i//2], i % 2)
randomOptions()
btnOK.clicked.connect(randomOptions)
self.setWindowTitle("PALCDMS")
比你想象的还要糟糕。你不是在添加文本,而是在创建大量新对象,并在每次单击时将它们添加到布局中。这比你想象的更糟糕。你不是在添加文本,而是在创建大量新对象,并在每次单击时将它们添加到布局中。非常感谢,我以前尝试过removeWidget,我想我只是在工作场所使用过它。非常感谢,我以前尝试过removeWidget,我想我只是在工作场所使用过它。