Python中的猜字游戏？

我上的是一门基础编程课，我一直在做这个游戏。这个想法是创建一个简单的单词猜测游戏，在这个游戏中，计算机会随机选择一个单词，你会尝试先猜测单词中的一些字母，然后在5次尝试后猜测单词本身。我已经经历了多次，但当我尝试运行模块时，仍然会出现“无效语法”错误。 说到编程语言，我有点诵读困难，所以也许我忽略了什么？ 如果有人能提供一些帮助，我将不胜感激

#Word Guessing Game
#Computer picks a random word
#Player tries to guess it
#computer only responds with yes or no

import random

tries = 0

print "Welcome to the word game!"
print "\nI'm going to think of a word and you have to guess it!"
print "\nGuess which letters are in the word, then you have to guess the whole thing!"
print "\nGood luck!"

WORDS = ("follow", "waking", "insane", "chilly", "massive", 
         "ancient", "zebra", "logical", "never", "nice")

word = random.choice(WORDS)

correct = word
length = len(word)
length = str(length)

guess = raw_input("The word is " + length + " letters long. Guess a letter!: ")

while tries < 5:
    for guess in word:
        if guess not in word:
            print "Sorry, try again."
        else:
            print "Good job! Guess another!"

    tries = tries + 1 #*

    if tries = 5:
        final = raw_input ("Try to guess the word!: ")

        if final = correct:
            print "Amazing! My word was ", word, "!"

        else:
            print "Sorry. My word was ", word, ". Better luck next time!"

raw_input("\n\nPress enter to exit")

猜单词游戏 #计算机随机挑选一个单词 #玩家试图猜测它 #计算机只响应是或否 随机输入 尝试=0 打印“欢迎来到文字游戏！” 打印“\n我想一个词，你必须猜出来！” 打印“\n根据单词中的字母，您必须猜出整个单词！” 打印“\n祝你好运！” 单词=（“跟随”，“清醒”，“疯狂”，“寒冷”，“巨大”， “古代”、“斑马”、“逻辑”、“从未”、“美好”） 单词=随机。选择（单词） 正确的 长度=长度（字） 长度=str（长度） 猜=原始输入（“单词是“+长度+”字母长。猜一个字母！：”） 当尝试<5时： 对于单词猜测： 如果猜测不在文字中： 打印“对不起，再试一次。” 其他： 打印“干得好！猜另一个！” 尝试=尝试+1#* 如果尝试次数=5： final=原始输入（“试着猜单词：”） 如果final=正确： 打印“太棒了！我的单词是”，单词“！” 其他： 打印“对不起，我的话是”，字，“祝你下次好运！” 原始输入（“\n\n按enter键退出”） 还应注意的是，问题发生在“while trys”块结束后，当时我试图指定“trys”变量的限制。我以前在一个随机数游戏中使用过它，但由于某些原因，它在这里不能正常工作。我将非常感谢您的帮助！ 还应该注意的是，我运行的是一个相当过时的Python版本，我相信是2.0的一些变体

    tries = tries + 1

    if tries == 5:
        final = raw_input ("Try to guess the word!: ")

        if final == correct:

您需要

=

进行比较，而不是

=

，

=

用于分配

您还可以将

tries=tries+1

替换为

tries+=1

您还希望将

raw_input

移动到循环内部，并在猜测完后，让用户在while之外猜测单词：

while tries < 5:
    guess = raw_input("The word is " + length + " letters long. Guess a letter!: ")
    if guess not in word: # use  `in` to check if the guess/letter is in the word
        print "Sorry, try again."
    else:
        print "Good job! Guess another!"

    tries += 1

# guesses are all used up when we get here
final = raw_input ("Try to guess the word!: ")

if final == correct:
    print "Amazing! My word was ", word, "!"

else:
    print "Sorry. My word was ", word, ". Better luck next time!"

尝试<5次时：
猜=原始输入（“单词是“+长度+”字母长。猜一个字母！：”）
如果猜测不在单词中：#使用'in'检查猜测/字母是否在单词中
打印“对不起，再试一次。”
其他：
打印“干得好！猜另一个！”
尝试次数+=1
#我们到这里时，猜测都用光了
final=原始输入（“试着猜单词：”）
如果final==正确：
打印“太棒了！我的单词是”，单词“！”
其他：
打印“对不起，我的话是”，字，“祝你下次好运！”

请试试这个

import random 

index = -1
infi = ("python","jumble","hide","mama")

word = random.choice(infi)
word_len = len(word)
guess = ""
attempt = 0
enter = ""
print(word)
temp = "_" * word_len

print("\t\t The word chosen by computer contain", word_len,"letters.")
print("\t  Tap any letter to check if this letter is in computer word.\n")
print("\t You got 5 attempts to check if tapped letter is in computer word.\n")
print("\t\t\t\t GOOD LUCK!!!\n\n\n\n")

for i in range(0, 5):
    attempt +=1
    guess = input("Attempt no. "+str(attempt)+":")
    if guess in word and guess != enter:
        for i in range(0, word_len):
            if guess == word[i]:
                temp = temp[:i] + guess +temp[i+1:]
        print("yes\n" + temp)  
    if guess not in word:
        print("no")
    if "_" not in temp:
        print("\t\t*********** Congratulation!! You guess the word *************")
        break
    elif attempt == 5:
        guess = input("And the word is:")
        if guess == word:

            print("\t\t*********** Congratulation!! You guess the word *************")
        else:
            print("\t\t*********** WRONG!! Shame on you *************")

---

对于单词中的猜测：你期望

做什么？@Hodge PodgeCrush，我清理了OP中的空白。确保带有
.*
的行在问题中的缩进与代码中的缩进相同。其他一切似乎都很好。