Python 为什么Taggit(Django Tag)赢了';一旦我使用Tag.models.all()就无法工作
我已经成功地实现了django taggit,直到我尝试使用mixin在本例中的“PropertyList”的ListView上呈现标记: 控制台一直在告诉我:Python 为什么Taggit(Django Tag)赢了';一旦我使用Tag.models.all()就无法工作,python,django,python-3.x,django-views,django-taggit,Python,Django,Python 3.x,Django Views,Django Taggit,我已经成功地实现了django taggit,直到我尝试使用mixin在本例中的“PropertyList”的ListView上呈现标记: 控制台一直在告诉我: NameError: name 'Tag' is not defined **问题显然来自views.py第4行 我不能像“PropertyList”那样从模型中导入“Tag”,因为它是第三方库 我已经试着进口了 from taggit.managers import TaggableManager 在views.py中,但出现相同
NameError: name 'Tag' is not defined
**问题显然来自views.py第4行
我不能像“PropertyList”那样从模型中导入“Tag”,因为它是第三方库
我已经试着进口了
from taggit.managers import TaggableManager
在views.py中,但出现相同错误
我使用的是django 2.1和django taggit 1.1.0
代码如下:
models.py
from taggit.managers import TaggableManager
class City(models.Model):
name = models.CharField(max_length=200)
slug = models.SlugField(max_length=250, unique=True)
tags = TaggableManager()
class Meta:
verbose_name_plural = 'Cities'
def __str__(self):
return self.name
class PropertyListing(models.Model):
name = models.CharField(max_length=200)
slug = models.SlugField(max_length=250, unique=True)
price = models.DecimalField(max_digits=10, decimal_places=2)
description = models.TextField(max_length=1000)
address = models.CharField(max_length=1000)
is_active = models.BooleanField(default=False)
city = models.ForeignKey(City, on_delete=models.CASCADE, related_name='property_listings')
class Meta:
verbose_name_plural = 'Properties Listings'
def __str__(self):
return self.name
def save(self, *args, **kwargs):
self.slug = slugify(self.name)
super(PropertyListing, self).save(*args, **kwargs)
def get_absolute_url(self):
return reverse('core:property_detail', kwargs={'pk': self.pk})
views.py
class TagMixin(object):
def get_context_data(self, **kwargs):
context = super(TagMixin, self).get_context_data(**kwargs)
context['tags'] = Tag.objects.all()
return context
class PropertyListingView(TagMixin, ListView):
model = City
model_type = PropertyImage
queryset = PropertyListing.objects.all()
context_object_name = 'properties'
template_name = 'core/property-listing.html'
def get_context_data(self, *args, **kwargs):
context = super(PropertyListingView, self).get_context_data(**kwargs)
context['cities'] = City.objects.all()
context['properties'] = PropertyImage.objects.select_related('image_property_listing')
return context
class CityTaggedView(TagMixin, ListView):
model = City
context_object_name = 'cities'
template_name = 'core/city-tagged.html'
def get_queryset(self):
return City.objects.filter(tags__slug=self.kwargs.get('slug'))
url.py
path('', PropertyListingView.as_view(), name='property_listing'),
path('tag/<slug:slug>/', CityTaggedView.as_view(), name='city_tagged')
path(“”,PropertyListingView.as_view(),name='property_listing'),
路径('tag/',CityTaggedView.as_view(),name='city_taged')
任何帮助都将不胜感激。我不明白为什么会发生这种情况。您只需导入
标签
模型,如:
# app/views.py
# import the Tag class
from taggit.models import Tag
class TagMixin(object):
def get_context_data(self, **kwargs):
context = super(TagMixin, self).get_context_data(**kwargs)
context['tags'] = Tag.objects.all()
return context
# ...
#app/views.py
#导入标记类
从taggit.models导入标记
类TagMixin(对象):
def获取上下文数据(自身,**kwargs):
context=super(TagMixin,self)。获取上下文数据(**kwargs)
上下文['tags']=Tag.objects.all()
返回上下文
#…
毕竟,您的代码使用了标记
,但您从未在views.py
文件中定义过它。这与Django或taggit本身没有多大关系,只是Python thaat不理解您使用Tag
的意思