在python中缩放元组中的每个元素

我有一个元组类型的数据，如下所示：

x =  (((-300, 49.3878), (-300, 400), (-220.045, 400), (-169.193, 204.22), (-300, 49.3878)))

我需要通过除以100来缩放元组中的每个元素。即，输出结果应为：

x'= (((-3.00, 0.493878), (-3.00, 4.00), (-2.20045, 4.00), (-1.69193, 2.0422), (-3.00, 0.493878)))

有人能告诉我怎么做吗？

使用嵌套的，如下所示

x =  (((-300, 49.3878), (-300, 400), (-220.045, 400), (-169.193, 204.22), (-300, 49.3878)))

y = tuple(tuple(i / 100.0 for i in inner) for inner in x)

# You can remove the tuple and instead use [] if you don't mind it being a list.
y_list = [[i / 100.0 for i in inner] for inner in x]

如下图所示，使用嵌套的

x =  (((-300, 49.3878), (-300, 400), (-220.045, 400), (-169.193, 204.22), (-300, 49.3878)))

y = tuple(tuple(i / 100.0 for i in inner) for inner in x)

# You can remove the tuple and instead use [] if you don't mind it being a list.
y_list = [[i / 100.0 for i in inner] for inner in x]

如下图所示，使用嵌套的

x =  (((-300, 49.3878), (-300, 400), (-220.045, 400), (-169.193, 204.22), (-300, 49.3878)))

y = tuple(tuple(i / 100.0 for i in inner) for inner in x)

# You can remove the tuple and instead use [] if you don't mind it being a list.
y_list = [[i / 100.0 for i in inner] for inner in x]

如下图所示，使用嵌套的

x =  (((-300, 49.3878), (-300, 400), (-220.045, 400), (-169.193, 204.22), (-300, 49.3878)))

y = tuple(tuple(i / 100.0 for i in inner) for inner in x)

# You can remove the tuple and instead use [] if you don't mind it being a list.
y_list = [[i / 100.0 for i in inner] for inner in x]

---

如果您使用Python2阻止任何整数（100的倍数除外）被“错误地”除，则可能值得除以

100.0

。如果您使用Python2阻止任何整数（100的倍数除外），则可能值得除以

100.0

被“不正确”分割。如果您使用python 2阻止任何整数（100的倍数除外）被“不正确”分割，则可能值得除以

100.0

。如果您使用python 2阻止任何整数（100的倍数除外）被“不正确”分割，则可能值得除以

100.0

。